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victus00 [196]
3 years ago
11

2900 dollars is placed in an account with an annual interest rate of 9%. How much will be in the account after 13 years, to the

nearest cent?
Mathematics
1 answer:
mr_godi [17]3 years ago
7 0

Answer:

$8,890.83

Step-by-step explanation:

To find the answer we have to use this equation:

A = P(1 + r)^t

A = The total amount

P = The initial amount

R = The interest rate

T = Time

Given in the question:

A = ?

P = 2,900

R = .09

T = 13

Plug it into the equation and solve:

A = 2900(1 + .09)^1^3\\A = 2900(1.09)^1^3\\A = 2900(3.065804612)\\A = 8890.83

Therefore, after 13 years there will be $8,890.83 in the account.

<em>I hope this helps!!</em>

<em>- Kay :)</em>

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It takes 80 gallons of water to fill up a bathtub. how many pints of water is this?
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Answer:

640

Step-by-step explanation:

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8 pints in a gallon

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640

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2 years ago
These two triangles are similar. What are a and b? Note: the two figures are not drawn to scale. Please help with this!
borishaifa [10]

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A.36 inches B.150 inches

Step-by-step explanation:

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Collection of domestic animals is a set. However, a collection of big domestic animal is not a set. How do you justify this stat
Schach [20]

Collection of domestic animals is a set. However, a collection of big domestic animal is not a set as it is a subset.

<h3>What are Domesticated animals?</h3>

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Note that Collection of domestic animals is a set but the collection of big domestic animal is a subset of domestic animals this is because the big domestic animal are part of the domestic animals and as such it will be a subset.

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2 years ago
Use logarithmic differentiation to find the derivative of the function. y = x2cos x Part 1 of 4 Using properties of logarithms,
Arisa [49]

ANSWER

{y}^{'}  = 2x \cos(x)  -   {x}^{2} \sin(x)

EXPLANATION

The given function is

y =  {x}^{2}  \cos(x)

We take natural log of both sides;

ln(y) =   ln({x}^{2}  \cos(x) )

Recall and use the product rule of logarithms.

ln(AB)  =  ln(A )  +  ln(B)

This implies that:

ln(y) =   ln({x}^{2}  ) +  ln( \cos(x) )

ln(y) =  2 ln({x} ) +  ln( \cos(x) )

We now differentiate implicitly to obtain;

\frac{ {y}^{'} }{y}  =  \frac{2}{x}   -  \frac{ \sin(x) }{ \cos(x) }

Multiply through by y,

{y}^{'} = y( \frac{2}{x}   - \frac{ \sin(x) }{ \cos(x) ) })

Substitute y=x²cosx to obtain;

{y}^{'} =  {x}^{2}  \cos(x) ( \frac{2}{x}   - \frac{ \sin(x) }{ \cos(x) ) } )

Expand:

{y}^{'}  = 2x \cos(x)  -   {x}^{2} \sin(x)

7 0
3 years ago
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