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Maurinko [17]
3 years ago
10

dle" class="latex-formula">
how to solve ??

​
Mathematics
1 answer:
Ghella [55]3 years ago
7 0

Answer:

8 \sqrt{72}  = 8 \sqrt{3 \times 3 \times 2 \times 2 \times 2}  \\  = 8 \times 3 \times 2  \times \sqrt{2}  = 48 \sqrt{2}

<h2><u>48√2</u> is the right answer.</h2>
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7th grade help me plzzzzz
Gekata [30.6K]

Answer:

fifteen, "number sentence"

Step-by-step explanation:

5 + 5 +5 = 15

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3x - 6 = 2 - 5x how do i get x
Elanso [62]

Answer:

x=0.875

Step-by-step explanation:

3x-6=2-5x

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3 years ago
Given f (x ) = x^2 + 3x + 2 and g (x ) = x + 1, perform the indicated operations.
Nana76 [90]

Answer:

(i) (f - g)(x) = x² + 2·x + 1

(ii) (f + g)(x) = x² + 4·x + 3

(iii) (f·g)(x) = x³ + 4·x² + 5·x + 2

Step-by-step explanation:

The given functions are;

f(x) = x² + 3·x + 2

g(x) = x + 1

(i) (f - g)(x) = f(x) - g(x)

∴ (f - g)(x) = x² + 3·x + 2 - (x + 1) = x² + 3·x + 2 - x - 1 = x² + 2·x + 1

(f - g)(x) = x² + 2·x + 1

(ii) (f + g)(x) = f(x) + g(x)

∴ (f + g)(x) = x² + 3·x + 2 + (x + 1) = x² + 3·x + 2 + x + 1 = x² + 4·x + 3

(f + g)(x) = x² + 4·x + 3

(iii) (f·g)(x) = f(x) × g(x)

∴ (f·g)(x) = (x² + 3·x + 2) × (x + 1) = x³ + 3·x² + 2·x + x² + 3·x + 2 = x³ + 4·x² + 5·x + 2

(f·g)(x) = x³ + 4·x² + 5·x + 2

7 0
3 years ago
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