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3 years ago

Round 564,938 to the nearest 1000 is it 565000

Mathematics

1 answer:

lord [1]3 years ago

4 0

Answer:

YES!

Step-by-step explanation:

564,938 -> 565,000

BRAINLIEST?

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What is the area help plssssssss

sergey [27]

Answer:

Im not 100% sure but i believe its M6?

Step-by-step explanation:

3 0

4 years ago

Plz help I have no idea how to answer it

saveliy_v [14]

5. Answer: see explanation

<u>Step-by-step explanation:</u>

If the roots are m and 3m, then x = m and x = 3m

⇒ x - m = 0 and x - 3m = 0

⇒ (x - m)(x - 3m) = 0

⇒ x² - 4mx + 3m² = 0

Since x² + px + q = 0 then p = -4m and q = 3m²

3p² = 3(-4m)² 16q = 16(3m²)

= 3(16m²) = 48m²

= 48m²

3p² = 48m² = 16q ⇒ 3p² = 16q

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6. Answer: 8 or 18

<u>Step-by-step explanation:</u>

The Area of the entire rectangle (A = L × w) is 12 × 10 = 120

The Area of the shaded region is 72, so the Area of the non-shaded region is 120 - 72 = 48.

There are two non-shaded triangles.

Bigger non-shaded Δ: L = 12-x, w = 10 ⇒ $A = \dfrac{10(12-x)}{2}$
Smaller non-shaded Δ: L = x, w = x ⇒ $A=\dfrac{x(x)}{2}$

Combine the Areas of both triangles and set it equal to the Area of the non-shaded region:

$\dfrac{x(x)}{2}+\dfrac{10(12-x)}{2}=48\\\\\\\dfrac{x^2}{2}+\dfrac{120-10x}{2}=48\\\\\\\dfrac{x^2-10x+120}{2}=48\\\\\\x^2-10x+120=96\\\\x^2-10x+24=0\\\\(x-4)(x-6)=0\\\\x - 4 = 0\quad or\quad x-6=0\\x=4\qquad or\qquad x=6\\\\\text{Based on the image provided, it appears that the x-value will be the}\\\text{smallest of the two possible solutions (4), but both solutions are valid.}$

Area of ΔBEF:

$\text{when x = 4, A =}\ \dfrac{4(4)}{2}=\dfrac{16}{2}=8\\\\\\\text{when x = 6, A =}\ \dfrac{6(6)}{2}=\dfrac{36}{2}=18$

5 0

3 years ago

Make sure to show how you got your answer

nordsb [41]

Answer: 0.075

Step-by-step explanation: when you are working with percentages to decimals you want to move the decimal two places to the left. If you are working with decimals and you want to make it a percentage you would move the decimal two places to the right.

8 0

3 years ago

Read 2 more answers

The pressure, p, with which water passes through a pipe varies inversely as the square of the pipe's radius, 2. If k is the cons

iragen [17]

The variation equation is p = kr^2

<h3>How to determine the variation equation?</h3>

The variables are give as:

Pressure = P

Radius= r

The direct variation from p to the square of r is represented as:

$p\ \alpha\ r^2$

Express as an equation

p = kr^2

Where k represents the constant of variation

Hence, the variation equation is p = kr^2