Can anyone solve this for me please?

Mathematics

1 answer:

gayaneshka [121]3 years ago

8 0

The answer to the question

You might be interested in

identify all of the central angles. please help me asap. i have to have this done soon! :( thann you so much!

vova2212 [387]

Answer:

see explanation

Step-by-step explanation:

Central angles are angles at the centre of the circle subtended by 2 radii

Angles that meet this criteria are

∠AOB, ∠BOC, ∠AOC

8 0

3 years ago

Any value that is set and cannot change is a variable.<br><br> A.True<br> B.False

Leni [432]

Thank you for posting your question here at brainly. Feel free to ask more questions.

The best and most correct answer among the choices provided by the question is <span>B.False</span><span> .</span><span>
</span><span>
Hope my answer would be a great help for you.</span>

7 0

3 years ago

[IMAGE ATTACHED]<br> I don’t understand this please help.

rusak2 [61]

Answer:

z+5+101=180°( being straight angle)
z=180°-106°
z=74°

<h3>hope it helps.</h3><h3>stay safe healthy and happy</h3><h3 />

5 0

3 years ago

18z 2+17z+4 I need to know what this is

balandron [24]

Answer:

18z 2+17z+4

Step-by-step explanation:

it hard try to give more point

4 0

3 years ago

Can someone solve this with steps cause idk how to solve the radicals

IceJOKER [234]

$\bf 343^{\frac{2}{3}}+36^{\frac{1}{2}}-256^{\frac{3}{4}}\qquad \begin{cases}
343=7\cdot 7\cdot 7\\
\qquad 7^3\\
36=6\cdot 6\\
\qquad 6^2\\
256=4\cdot 4\cdot 4\cdot 4\\
\qquad 4^4
\end{cases}\\\\\\ (7^3)^{\frac{2}{3}}+(6^2)^{\frac{1}{2}}-(4^4)^{\frac{3}{4}}
\\\\\\
\sqrt[3]{(7^3)^2}+\sqrt[2]{(6^2)^1}-\sqrt[4]{(4^4)^3}\implies \sqrt[3]{(7^2)^3}+\sqrt[2]{(6^1)^2}-\sqrt[4]{(4^3)^4}
\\\\\\
7^2+6-4^3\implies 49+6-64\implies -9$

to see what you can take out of the radical, you can always do a quick "prime factoring" of the values, that way you can break it in factors to see who is what.

8 0

3 years ago