a. An asset that generates $7200 yearly income if the interest rate 5% compounded continuously, then its capital value is $140433.002
b. An asset that generates $7200 yearly income if the interest rate 10% compounded continuously, then its capital value is $68460.59
<u>Step-by-step explanation:</u>
For continuously compound interest
---------------> eq.1
Where
P = principal amount (initial investment)
r = annual interest rate (as a decimal)
t = number of years
A = amount after time t.
Let’s solve the equation
Where,
P is unknown
A = P + 7200 (asset after 1 year) ---------------> eq. 2
<u>Case A:
</u>

t = 1 (1 year)
Substitute all values in the formula (2) using the formula (1),






<u>Case B:</u>

t = 1 (1 year)
Substitute all values in the formula (2) using the formula (1),






Answer:
Step-by-step explanation:
I don't say you must have to mark my ans as brainliest but if you think it has really helped you plz don't forget to thank me my frnd...
Okay here it is
Y- 2 = 3 (X- 2)
And do you have the Y intercept? Because so far your slope intercept equation is
Y = 3x + ____
The scale 0.5 in : 6 ft, means that
any distance of 0.5 in on paper, represents 6 ft in reality
for example:
0.5*2= 1(in) represents 6*2=12 (ft)
0.5*4= 2(in) represents 6*4=24 (ft)
0.5*10=5(in) represents 6*10=60 (ft) and so on...
Let the wall be x (in) in the drawing:
0.5 (in) represents 6 (ft),
x (in) represents 30 (ft)
----------------------------------------
thus x = (0.5*30)/6 = 15/6= 2.5 (in)
Answer: 2.5 in