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lana66690 [7]
3 years ago
7

Expand and simplify (x-3)(x+7)

Mathematics
2 answers:
dedylja [7]3 years ago
7 0
X(x+7) -3(x+7)
x² + 7x -3x -21
x² +4x -21

that's the answer
if you understand and it's correct. don't forget to make my answer the brainliest
andreev551 [17]3 years ago
3 0
Let's multiply each term for the other one.

I mean: x*x; x+7; -3*x; -3*7

So x²+7x-3x-21

We add up like terms.

Final answer: x²+4x-21
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Using point-slope form, write the equation of the line that passes through (2, –1) and has a slope of –5.
erik [133]

Answer: (y+1)=5(x+2)

Step-by-step explanation:

6 0
2 years ago
Let g(x) = 2x and h(x)= x^2 -4. find (g o h)(0)
finlep [7]
The answer is -8

====================================================

Explanation:

There are two ways to get this answer

Method 1 will have us plug x = 0 into h(x) to get
h(x) = x^2 - 4
h(0) = 0^2 - 4
h(0) = 0 - 4
h(0) = -4
Then this output is plugged into g(x) to get
g(x) = 2x
g(-4) = 2*(-4)
g(-4) = -8 which is the answer
This works because (g o h)(0) is the same as g(h(0)). Note how h(0) is replaced with -4
So effectively g(h(0)) = -8 which is the same as (g o h)(0) = -8

-----------------------

The second method involves a bit algebra first
Start with the outer function g(x). Then replace every x with h(x). On the right side, we will replace h(x) with x^2-4 because h(x) = x^2-4

g(x) = 2x
g(x) = 2( x )
g(h(x)) = 2( h(x) ) ... replace every x with h(x)
g(h(x)) = 2( x^2-4 ) ... replace h(x) on the right side with x^2-4
g(h(x)) = 2x^2-8
(g o h)(x) = 2x^2-8

Now plug in x = 0
(g o h)(x) = 2x^2-8
(g o h)(0) = 2(0)^2-8
(g o h)(0) = 2(0)-8
(g o h)(0) = 0-8
(g o h)(0) = -8

Regardless of which method you use, the answer is -8

5 0
3 years ago
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Answer:

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Step-by-step explanation:

4 0
3 years ago
Given the functions f(x) = 3x²+5x-8 and g(x) = 2x²+4x-9<br><br> Find f(x) + g(x) and g(x) -f(x)
evablogger [386]
F(x) + g(x) = 5x^2 + 9x - 17; g(x) -f(x) = -x^2 -x -1
4 0
3 years ago
(07.02 MC)
BigorU [14]

Y=6 In this equation you also use combine like terms .

3 0
3 years ago
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