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ELEN [110]
3 years ago
6

What is an equation that passes through (18,2) and is parallel to 3y-x=-12

Mathematics
1 answer:
MrRa [10]3 years ago
5 0
3(2)-18=-12
6-18 = -12
-12 = -12
You might be interested in
Question 3 of 10
MrMuchimi

Answer:

The point-slope form  of the line is:

y + 4 = 4(x+3)

Hence, option B is correct.

Step-by-step explanation:

We know the point-slope form of the line equation is

y-y_1=m\left(x-x_1\right)

where

  • m is the slope of the line
  • (x₁, y₁) is the point

Given

The slope m = 4

From the graph, we can take the point (-3, -4)

So, in our case:

(x₁, y₁) = (-3, -4)

m = 4

now substituting m = 4 and (x₁, y₁) = (-3, -4) in the point-slope form of the line equation

y-y_1=m\left(x-x_1\right)

y - (-4) = 4(x - (-3))

y + 4 = 4(x+3)

Therefore, the point-slope form  of the line is:

y + 4 = 4(x+3)

Hence, option B is correct.

  • The graph of the line is also attached.

6 0
3 years ago
It takes 16 minutes for 9 people to paint 8 walls . How many minutes does it take for 4 people to paint 6 walls?
Soloha48 [4]

Answer:

27 minutes to complete the painting of 4 walls

Step-by-step explanation:

since 16m with 9p --> 8 walls

x minutes with 4p --> 6 walls?

let x= minutes

6 walls painted=(8/144 walls painted per minute)x

simplify

x= 6 divided by (8/144)

x=108 minutes (to complete 6 walls)

108/4=

27 minutes to complete the painting of 4 walls

4 0
3 years ago
Read 2 more answers
Let f(x)=5(x^2-3)+10. which statement must be true?
Maslowich
Find where the expression
x
−
5
x
2
−
25
x
-
5
x
2
-
25
is undefined.
x
=
−
5
,
x
=
5
x
=
-
5
,
x
=
5
Since
x
−
5
x
2
−
25
x
-
5
x
2
-
25
→
→
−
∞
-
∞
as
x
x
→
→
−
5
-
5
from the left and
x
−
5
x
2
−
25
x
-
5
x
2
-
25
→
→
∞
∞
as
x
x
→
→
−
5
-
5
from the right, then
x
=
−
5
x
=
-
5
is a vertical asymptote.
x
=
−
5
x
=
-
5
Consider the rational function
R
(
x
)
=
a
x
n
b
x
m
R
(
x
)
=
a
x
n
b
x
m
where
n
n
is the degree of the numerator and
m
m
is the degree of the denominator.
1. If
n
<
m
n
<
m
, then the x-axis,
y
=
0
y
=
0
, is the horizontal asymptote.
2. If
n
=
m
n
=
m
, then the horizontal asymptote is the line
y
=
a
b
y
=
a
b
.
3. If
n
>
m
n
>
m
, then there is no horizontal asymptote (there is an oblique asymptote).
Find
n
n
and
m
m
.
n
=
1
n
=
1
m
=
2
m
=
2
Since
n
<
m
n
<
m
, the x-axis,
y
=
0
y
=
0
, is the horizontal asymptote.
y
=
0
y
=
0
There is no oblique asymptote because the degree of the numerator is less than or equal to the degree of the denominator.
No Oblique Asymptotes
This is the set of all asymptotes.
Vertical Asymptotes:
x
=
−
5
x
=
-
5
Horizontal Asymptotes:
y
=
0
y
=
0
No Oblique Asymptotes
5 0
3 years ago
Help!!! I need to find the x and y values
gayaneshka [121]

The solution is that x = 26 and y = 9.

In order to find these, we need to note that since the two angles involving x's make a straight line, then they must equal 180 degrees. So we can add them together and set them equal to solve for x.

5x - 17 + 3x - 11 = 180 ----> combine like terms

8x - 28 = 180 ----> add 28 to both sides

8x = 208 -----> divide by 8

x = 26

Now that we have the value of x, we can find the value of the 3x - 11 term. That along with the right angle and the 2y + 5 angle combine to make another straight line. So we can solve by setting that equal to 180 as well.

3x - 11 + 90 + 2y + 5 = 180 ------> Combine like terms

3x + 2y + 84 = 180 -----> Put 26 in for x.

3(26) + 2y + 84 = 180 -----> Multiply

78 + 2y + 84 = 180 ------> Combine like terms again

2y + 162 = 180 ------> Subtract 162 from both sides

2y = 18 -----> Divide by 2

y = 9

6 0
3 years ago
Jasmine's school is selling tickets to a choral performance. On the first day of ticket sales the school sold 11 senior tickets
nikdorinn [45]

If we make s = Senior tickets,  

11s+1s

to find the values of c and s,w

If we express s in terms of c on t

s=21-2c

replacing this value on the first equation, we obtain

11(21-2c)+4c=123\\11.21-22c+4c=123\\231-18c=123\\231=123+18c\\231-123=18c\\108=18c\\c=\frac{108}{18} \\c=6

Placing c=6 on s=21-2c, we have

s=21-2(6)\\s=21-12\\s=9

Thus the senior ticket costs $9 and the child ticket cost $6

PLEASE MARK ME AS BRAINLIEST

3 0
3 years ago
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