The first thing to do is to clear the equation of fractions by multiplying by its LCM, which is 6 in this case. When you do that, you will get the equation
4p + 36 = 7p. Much easier to deal with, right? Now move the 4p over by subrtracting it: 36 = 3p, and p = 12
Answer:
A.
Jada should have multiplied both sides of the equation by 108.
Step-by-step explanation:
-4/9=x/108
you must multiply both sides
108*-4/9 = x*108
=-9/4
Answer:
(3, 4)
Step-by-step explanation:
A function is a relation that maps elements from a set (the domain, the set of the inputs) into elements from another set (the range, the set of the outputs).
Such that a function can map each element of the domain into only one element of the range.
Then, if a "function" has:
f(x1) = y1
and
f(x1) = y2
It is mapping the input "x1" into two different outputs, then this is not a function.
Now, we know that the ordered pair (3, -4) is among the points on the graph of the function f(x)
(The first value is the input and the second one is the output)
Then the point that does not belong to the graph, is the point that has the same input and different output.
(3, 4)
Any of the other points could belong to the graph.
Answer:
Option C.
Step-by-step explanation:
Note: x is missing in the second equation.
The given equations are
It can we written as
![\left[\left.\begin{matrix}4 & -7\\ -2 & 6\end{matrix}\right|\begin{matrix}-12\\ 11\end{matrix}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cleft.%5Cbegin%7Bmatrix%7D4%20%26%20-7%5C%5C%20-2%20%26%206%5Cend%7Bmatrix%7D%5Cright%7C%5Cbegin%7Bmatrix%7D-12%5C%5C%2011%5Cend%7Bmatrix%7D%5Cright%5D)
Divide row 1 be 4.
![\left[\left.\begin{matrix}1 & -\dfrac{7}{4}\\ -2 & 6\end{matrix}\right|\begin{matrix}-3\\ 11\end{matrix}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cleft.%5Cbegin%7Bmatrix%7D1%20%26%20-%5Cdfrac%7B7%7D%7B4%7D%5C%5C%20-2%20%26%206%5Cend%7Bmatrix%7D%5Cright%7C%5Cbegin%7Bmatrix%7D-3%5C%5C%2011%5Cend%7Bmatrix%7D%5Cright%5D)
Applying 
, we get
![\left[\left.\begin{matrix}1 & -\dfrac{7}{4}\\ 0 & \dfrac{5}{2}\end{matrix}\right|\begin{matrix}-3\\ 5\end{matrix}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cleft.%5Cbegin%7Bmatrix%7D1%20%26%20-%5Cdfrac%7B7%7D%7B4%7D%5C%5C%200%20%26%20%5Cdfrac%7B5%7D%7B2%7D%5Cend%7Bmatrix%7D%5Cright%7C%5Cbegin%7Bmatrix%7D-3%5C%5C%205%5Cend%7Bmatrix%7D%5Cright%5D)
Applying 
, we get
![\left[\left.\begin{matrix}1 & -\dfrac{7}{4}\\ 0 & 1\end{matrix}\right|\begin{matrix}-3\\ 2\end{matrix}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cleft.%5Cbegin%7Bmatrix%7D1%20%26%20-%5Cdfrac%7B7%7D%7B4%7D%5C%5C%200%20%26%201%5Cend%7Bmatrix%7D%5Cright%7C%5Cbegin%7Bmatrix%7D-3%5C%5C%202%5Cend%7Bmatrix%7D%5Cright%5D)
Applying 
, we get
![\left[\left.\begin{matrix}1 & 0\\ 0 & 1\end{matrix}\right|\begin{matrix}\dfrac{1}{2}\\ 2\end{matrix}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cleft.%5Cbegin%7Bmatrix%7D1%20%26%200%5C%5C%200%20%26%201%5Cend%7Bmatrix%7D%5Cright%7C%5Cbegin%7Bmatrix%7D%5Cdfrac%7B1%7D%7B2%7D%5C%5C%202%5Cend%7Bmatrix%7D%5Cright%5D)
Since 
, therefore required ordered pair is 
.
Hence, option C is correct.
