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katrin [286]
3 years ago
5

A, B & C lie on a straight line. D, C & E lie on a different straight line.Angle y = 102° and angle Z = 57°.Work out x,

explaining each stage of your working in the comment box.

Mathematics
1 answer:
sergey [27]3 years ago
4 0

Answer:

lefjiiofrioropr

Step-by-step explanation:

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Use the graph to complete the table.<br><br> X Y<br> 6 1<br> 8 3<br> 10 <br> 7<br> 14
tester [92]

Answer:

X     Y

6      1

8      3

10     5

7       2

14      9

Step-by-step explanation:

X - 5 =Y

3 0
2 years ago
Simplify the expression 4+2(6+1)+5(5-2)
aev [14]

Answer:

33

Step-by-step explanation:

Use PEMDAS, so the first thing you solve is what's in the parenthesis.

(6 + 1) = 7

(5 -2) = 3

So now your equation looks like 4 + 2 x 7 + 5 x 3

Now multiply the numbers needed

2 x 7 = 14

5 x 3 = 15

So now it looks like 4 + 14 + 15

Simplify

4 + 14 = 18 + 15 = 33

8 0
3 years ago
Read 2 more answers
We choose a number from the set 1, 2, 3,..., 100 uniformly at random and denote this number by X. For each of the following choi
kiruha [24]

Answer:

(a) A and B are dependent.

(b) C and D are dependent.

(c) E and F are dependent.

Step-by-step explanation:

Two sets are said to be independent if the intersection of the two set is empty. That is the sets are disjoint.

Let's examine the situations to determine if they are independent or not.

(a) A = {2, 4, 6, . . . , 10, . . . , 20, . . .} and B = {5, 10, 15, . . . , 20, . . .}. Since A n B = {10, 20, . . .}, then the sets are dependent

(b) C = {10, 11, 12, . . . , 31, . . . , 62, . . . , 93, . . .} and D = {31, 62, 93}. Since C n D = {31, 62, 93}, then the sets are dependent.

(c) E = {5, 7, 11, . . .} and F = {5, 15, . . .}. Since E n F = {5}, then the set are dependent.

Thus

(a) A and B are dependent.

(b) C and D are dependent.

(c) E and F are dependent.

5 0
3 years ago
Create a graph that has the following intercepts. Make sure to label each of the intercepts on
SCORPION-xisa [38]

Answer:

  see below for the graph

Step-by-step explanation:

The desired graph has two y-intercepts and one x-intercept. It is not the graph of a function.

Here's one way to get there.

__

Start with the parent function y = |x| and scale it down so that it has a y-intercept of -1 and x-intercepts at ±1.

Now, it is ...

  f(x) = |x| -1

We want to scale this vertically by a factor of -5. this puts the y-intercept at +5 and leaves the x-intercepts at ±1.

Horizontally, we want to scale the function by an expansion factor of 3. The transformed function g(x) will be ...

  g(x) = -5f(x/3) = -5(|x/3| -1) = -5/3|x| +5

This function has two x-intercepts at ±3 and one y-intercept at y=5. By swapping the x- and y-variables, we can get an equation for the graph you want:

  x = -(5/3)|y| +5

______

<em>Comment on this answer</em>

Since there are no requirements on the graph other than it have the listed intercepts, you can draw it free-hand through the intercept points. It need not be describable by an equation.

7 0
3 years ago
ANSWERED
kvv77 [185]

Answer:

c but you have it so thanks

Step-by-step explanation:

6 0
3 years ago
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