Answer: The area is 530 square units
Step-by-step explanation: The diameter of the circle has been given as 26. That makes the radius 13, that is;
Radius = diameter/2
Radius = 26/2
Radius = 13
The area of a circle is derived by the formula;
Area = pi x r^2
Where pi is 3.14 and r is 13,
Area = (3.14) x 13^2
Area = 3.14 x 169
Area = 530.66
Approximately to the nearest hundred of a square unit,
The area of the circle is 530 square units
Answer:
The volume of the prism is equal to the volume of the cylinder
Step-by-step explanation:
For each solid figure, the volume formula is ...
V = Bh
where B is the cross-sectional area and h is the height. The problem statement tells us B and h have the same values for both figures. Hence their volumes are the same.
Answer:
Isolating a variable means rearranging an algebraic equation so that a different variable is on its own. The goal is to choose a sequence of operations that will leave the variable of interest on one side and put all other terms on the other side of the equal sign.
Step-by-step explanation:
Answer:
(E) 0.71
Step-by-step explanation:
Let's call A the event that a student has GPA of 3.5 or better, A' the event that a student has GPA lower than 3.5, B the event that a student is enrolled in at least one AP class and B' the event that a student is not taking any AP class.
So, the probability that the student has a GPA lower than 3.5 and is not taking any AP classes is calculated as:
P(A'∩B') = 1 - P(A∪B)
it means that the students that have a GPA lower than 3.5 and are not taking any AP classes are the complement of the students that have a GPA of 3.5 of better or are enrolled in at least one AP class.
Therefore, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
Where the probability P(A) that a student has GPA of 3.5 or better is 0.25, the probability P(B) that a student is enrolled in at least one AP class is 0.16 and the probability P(A∩B) that a student has a GPA of 3.5 or better and is enrolled in at least one AP class is 0.12
So, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
P(A∪B) = 0.25 + 0.16 - 0.12
P(A∪B) = 0.29
Finally, P(A'∩B') is equal to:
P(A'∩B') = 1 - P(A∪B)
P(A'∩B') = 1 - 0.29
P(A'∩B') = 0.71
