A container filled with gas is connected to an open-end manometer that is filled with mineral oil. the pressure in the gas conta
iner is 753 mm hg and atmospheric pressure is 724 mm. how high will the level rise in the manometer if the densities of hg and mineral oil are 13.6 g/ml and 0.822 g/ml respectively?
<span>The difference in pressure is equal to the pressure exerted by the displaced fluid.
Since the Pressure difference is equal, density of fluid is inversely proportional to the height of the column of displaced fluid => (Ď1)(h1) = (Ď2)(h2)
(13.6 g/ml)(753 - 724 mm Hg) = (0.822 g/ml)(h2)
h2 = (13.6 g/ml)(753 - 724 mm Hg) / (0.822 g/ml)
h2 = 480 mm</span>
Okay Mr (H2O)= 18g therefore moles of H2O is 720.8/18= 40.04mol the ratio of H2 to O2 to H2O is 2 : 1 : 2 so moles of H2 is same as H2O here H2= 40.04moles
moles of O2 is half so 40.04 x 0.5 20.02moles
grams of O2 is its moles into Mr of O2 that's 20.02 x 32 = 640.64g
