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alexandr402 [8]
3 years ago
9

32. Calculate the pH of a solution at 1.00 x 10- MIH") and identify the substance as an acid or base,

Chemistry
1 answer:
Gre4nikov [31]3 years ago
8 0

Answer:

{ \boxed{ \tt{formular : pH =  -  log[H {}^{ + } ]}}} \\ pH =  -  log(1.00 \times  {10}^{-6} ) = 6: it's an acid\\ since \: we \: lack \: the \: exponent, \: this \: question \: is \: unsolvable \\ { \green{ \bf{take \: note}}} :{ \tt{pH \: below \: 7 \: that \: is \: { \red{acidic}}.  \:  \:  pH \: greater \: than \: 7 \: is \: { \red {basic}}}}

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The density of aluminum is 2.70 g/cm3. Apiece of aluminum foil that is 1000 cm on each side has a mass of 440. mg. How thick is
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Mass/volume = density
mass = (440 mg)*(1g)/(1000mg) = 0.440g
volume = (1000cm)(1000cm)(t)
where t = thickness
density = 2.70 g/cm^3 = (0.440g)/((1000cm)(1000cm)(t))

multiply both sides by 't' and divide both sides by (2.70g/cm^3)

t = (0.440) / ((1000cm)(1000cm)(2.70)) = 1.629x10^-7 cm

t = (1.629 x 10^-7 cm)*(1000000 micrometers)/(1 cm) = 0.1629 micrometers

Answer is t = 0.1629 micrometers
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