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alexandr402 [8]
3 years ago
9

32. Calculate the pH of a solution at 1.00 x 10- MIH") and identify the substance as an acid or base,

Chemistry
1 answer:
Gre4nikov [31]3 years ago
8 0

Answer:

{ \boxed{ \tt{formular : pH =  -  log[H {}^{ + } ]}}} \\ pH =  -  log(1.00 \times  {10}^{-6} ) = 6: it's an acid\\ since \: we \: lack \: the \: exponent, \: this \: question \: is \: unsolvable \\ { \green{ \bf{take \: note}}} :{ \tt{pH \: below \: 7 \: that \: is \: { \red{acidic}}.  \:  \:  pH \: greater \: than \: 7 \: is \: { \red {basic}}}}

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Answer: -

6

Explanation: -

The given unbalanced chemical equation is As + NaOH -- > Na3AsO3 + H2

We see there 3 sodium on the right side from Na3AsO3.

But there are only 1 sodium on the left from NaOH.

So we multiply NaOH by 3.

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Now we see the number of Hydrogen on the left is 3.

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So, we multiply to get both sides 6 hydrogen.

As + 6NaOH -- > Na3AsO3 + 3 H2

Rebalancing for Na,

As + 6NaOH -- > 2Na3AsO3 + 3 H2.

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