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3 years ago

The value of delta G at 141.0 degrees celsius for the formation of phosphorous trichloride from its constituent elements,

Chemistry

1 answer:

AURORKA [14]3 years ago

6 0

Answer:

The correct answer is option E.

Explanation:

The Gibbs free energy is given by expression:

ΔG = ΔH - TΔS

ΔH = Enthalpy change of the reaction

T = Temperature of the reaction

ΔS = Entropy change

We have :

ΔH = -720.5 kJ/mol = -720500 J/mol (1 kJ = 1000 J)

ΔS = -263.7 J/K

T = 141.0°C = 414.15 K

$\Delta G = -720500 J/mol - (414.15 K\times (-263.7 J/K))$

$= -611,288.64 J/mol = -611.28 kJ/mol\approx -611.3 kJ/mol$

The Gibb's free energy of the given reaction at 141.0°C is -611.3 kJ/mol.

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How many grams of NaCl are required to make 150.0 mL of a 5.000 m solution

Oksi-84 [34.3K]

The grams of NaCl that are required to make 150.0 ml of a 5.000 M solution is 43.875 g

calculation

Step 1:calculate the number of moles

moles = molarity x volume in L

volume = 150 ml / 1000 = 0.15 L

= 0.15 L x 5.000 M = 0.75 moles

Step 2: calculate mass

mass = moles x molar mass

molar mass of NaCl = 23 + 35.5 = 58.5 mol /L

mass is therefore =0.75 moles x 58.5 mol /l =43.875 g

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3 years ago

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Vinil7 [7]

Answer:

Properties of transition elements

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3 years ago

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A car engine produces 604 kJ of mechanical energy from fuel capable of producing 2416 kJ of energy. The efficiency of the engine

Anna71 [15]

I think it’s 40% but I’m not sure

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3 years ago

If a gas occupies 1532.7 mL at standard temperature, what volume does it occupy at 49.4 ºC if the pressure remains constant?

ElenaW [278]

Answer:

a. 1810mL

Explanation:

When conditions for a gas change under constant pressure (and the number of molecules doesn't change), it follows Charles' Law:

$\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}$ where the temperatures must be measured in Kelvin

To convert from Celsius to Kelvin, add 273, or use the equation: $T_C+273=T_K$

For this problem, one must also recall that standard temperature is 0°C (or 273K).

So, $T_1 = 273[K]$ , and $T_2 = (49.4+273)[K]=322.4[K]$ .

$\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}$

$\dfrac{(1532.7[mL])}{(273[K])}=\dfrac{V_2}{(322.4[K])}$

$\dfrac{(1532.7[mL])}{(273[K\!\!\!\!\!{-}])}(322.4[K\!\!\!\!\!{-}] )=\dfrac{V_2}{(322.4[K]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})}(322.4[K]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})$

$1810.04571428[mL]=V_2$

Adjusting for significant figures, this gives $V_2=1810[mL]$

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2 years ago

How does Arizona's climate relate to the air and ocean currents?

harkovskaia [24]

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Explanation:

https://www.edf.org/climate/costofinaction- this is where I gathered this info. Not mine. But I hope it helps!

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3 years ago