Answer:
B. (10,4)
Step-by-step explanation:
Let x be the independent variable and y represents the dependent variable in the graph,
∵Graph represents the direct variation,
⇒ y ∝ x
⇒ y = kx
Where, k is the proportionality constant.
Here, k = 0.4,
⇒ Equation that shows in the graph would be,
y = 0.4x
At (4, 10),
10 = 0.4(4) ( False ),
⇒ (4, 10) is not in the graph.
At (10, 4),
4 = 0.4(10) ( True )
⇒ (10, 4) is on the graph.
At (0.04, 10),
10 = 0.4(0.04) ( false )
⇒ (0.04, 10) is not on the graph.
At (10, 0.04),
0.04 = 0.4(10) ( false )
⇒ (10, 0.04) is not on the graph.
Interesting problem ...
The key is to realize that the wires have some distance to the ground, that does not change.
The pole does change. But the vertical height of the pole plus the distance from the pole to the wires is the distance ground to the wires all the time. In other words, for any angle one has:
D = L * sin(alpha) + d, where D is the distance wires-ground, L is the length of the pole, alpha is the angle, and 'd' is the distance from the top of the (inclined) pole to the wires:
L*sin(40) + 8 = L*sin(60) + 2, so one can get the length of the pole:
L = (8-2)/(sin(60) - sin(40)) = 6/0.2232 = 26.88 ft (be careful to have the calculator in degrees not rad)
So the pole is 26.88 ft long!
If the wires are higher than 26.88 ft, no problem. if they are below, the concerns are justified and it won't pass!
Your statement does not mention the distance between the wires and the ground. Do you have it?
11y-36= 63° because of the angles theorem.
Answer:
C number of binders because the teacher would have to order binders depending on how many students there are.
Step-by-step explanation:
Answer:
1 cm
Step-by-step explanation:
To solve this problem we can use the Pythagorean theorem. In fact the diagonal of a rectangle is an hypotenuse of a right triangle, while the length is a leg. The width is the other leg
width = √2^2 - (√3)^2 = √4 - 3 = √1 = 1 cm
