Perimeter of rectangle=66
length of rectangle=L
width of rectangle=w
P of a rect.= 2(length)+ 2(width)
66= 2L+2w
if the length is 7in more than the width, then
L=7+w
Now we will substitute 7+w in for L. Here is our new equation:
66=2(7+w) + 2w
Solve for w 
66=14+2w+2w
66=14+4w
52=4w
w=13
L=7+13, so L=20
I hooe this is explained well enough
        
             
        
        
        
Answer:
Step-by-step explanation:
A)8
 
        
                    
             
        
        
        
Answer:
18.5
Step-by-step explanation:
 
        
                    
             
        
        
        
Answer: (3,1)
Explanation:
        
                    
             
        
        
        
A. 
4(19x + 16) 
Hope this helps!