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Reil [10]
3 years ago
14

HELPPP PLS ASAPPPPPP Identify a diameter of circle E.

Mathematics
1 answer:
timurjin [86]3 years ago
8 0

Answer: B). HI

Step-by-step explanation:

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2 fraction bars. The first bar is labeled 1 with 8 boxes underneath that are labeled one-eighth. The second bar is labeled 1 wit
GaryK [48]

Answer:

Sorry for the late reply but the answer is 3/8

Step-by-step explanation:

Just trust me i took it on edge

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Laura cuts 64 inches of ribbon into two parts and give her mom one part. Laura's part is 28 inches long. Her mom cuts her ribbon
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6x+28=64\\\\6x=36\ /:6\\\\x=6
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Billy was counting the number of wheels and bike seats at the playground. He saw tricycles and bicycles. He counted 79 wheels an
mart [117]
I think the answer is 25.5. Although, I don't know how you would have half a bike unless there was a 3 wheel bike which would make the answer 24.
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3 years ago
The mean life of a television set is 119119 months with a standard deviation of 1414 months. If a sample of 7474 televisions is
Pepsi [2]

Answer:

0.5034 = 50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean

In this problem, we have that:

\mu = 119, \sigma = 14, n = 74, s = \frac{14}{\sqrt{74}} = 1.6275

What is the probability that the sample mean would differ from the true mean by less than 1.11 months?

This is the pvalue of Z when X = 119 + 1.1 = 120.1 subtracted by the pvalue of Z when X = 119 - 1.1 = 117.9. So

X = 120.1

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{120.1 - 119}{1.6275}

Z = 0.68

Z = 0.68 has a pvalue of 0.7517

X = 117.9

Z = \frac{X - \mu}{s}

Z = \frac{117.9 - 119}{1.6275}

Z = -0.68

Z = -0.68 has a pvalue of 0.2483

0.7517 - 0.2483 = 0.5034

0.5034 = 50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

3 0
3 years ago
How do the graphs of the functions f(x) = (Three-halves)x and g(x) = (Two-thirds)x compare?
miss Akunina [59]

Answer:

The answer to this question can be defined as follows:

Step-by-step explanation:

Given:

\bold{f(x)= (\frac{3}{2})^x}\\\\\bold{g(x)= (\frac{2}{3})^x}\\

Following are the graph attachment to this question:

The second function, that is g(x)= (\frac{2}{3})^x is not even a function.

Remember that g(x) function is the inverted f(x) function. And when you see this pattern, a reflection on the Y-axis expects you.

Reflection in the axis.

In x-axis:

Increase the function performance by -1 to represent an exponential curve around the x-axis.

In y-axis:

Increase the input of the function by -1 to represent the exponential function around the y-axis.

8 0
3 years ago
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