D. Although I'm not 100% sure
You plug in 2x + 4 into the y for the other equation (3x +y ) and solve for it
Answer:
4/125
Step-by-step explanation:
I think it is D
Hope my answer help you?
Answer:
18.7939 m
Step-by-step explanation:
-Let x be the distance between John and clock tower.
-Let y be the vertical distance from the eyes of the two men standing to the top of the clock tower.
#Taking the right triangle ACD:
![\Tan \ theta=\frac{Perpendicular \ Height}{Base}\\\\Tan \ 60\textdegree=\frac{y+1.5}{x}\\\\y=x \ Tan \ 60\textdegree -1.5](https://tex.z-dn.net/?f=%5CTan%20%5C%20theta%3D%5Cfrac%7BPerpendicular%20%5C%20Height%7D%7BBase%7D%5C%5C%5C%5CTan%20%5C%2060%5Ctextdegree%3D%5Cfrac%7By%2B1.5%7D%7Bx%7D%5C%5C%5C%5Cy%3Dx%20%5C%20Tan%20%5C%2060%5Ctextdegree%20-1.5)
#Taking the right triangle ABD:
![\Tan \ theta=\frac{Perpendicular \ Height}{Base}\\\\Tan \ 40\textdegree=\frac{y+1.5}{x+20}\\\\y=(x+20)\ Tan \ 40\textdegree -1.5](https://tex.z-dn.net/?f=%5CTan%20%5C%20theta%3D%5Cfrac%7BPerpendicular%20%5C%20Height%7D%7BBase%7D%5C%5C%5C%5CTan%20%5C%2040%5Ctextdegree%3D%5Cfrac%7By%2B1.5%7D%7Bx%2B20%7D%5C%5C%5C%5Cy%3D%28x%2B20%29%5C%20Tan%20%5C%2040%5Ctextdegree%20-1.5)
#We equate the two yo solve for x and y;
![(x+20)\ Tan \ 40\textdegree -1.5=x\ Tan \ 60\textdegree -1.5\\\\(x+20)\ Tan \ 40\textdegree=x\ Tan \ 60\textdegree\\\\0.8391x+16.7820=1.7321x\\\\x=18.7939](https://tex.z-dn.net/?f=%28x%2B20%29%5C%20Tan%20%5C%2040%5Ctextdegree%20-1.5%3Dx%5C%20Tan%20%5C%2060%5Ctextdegree%20-1.5%5C%5C%5C%5C%28x%2B20%29%5C%20Tan%20%5C%2040%5Ctextdegree%3Dx%5C%20Tan%20%5C%2060%5Ctextdegree%5C%5C%5C%5C0.8391x%2B16.7820%3D1.7321x%5C%5C%5C%5Cx%3D18.7939)
Hence, John's distance from the tower's base is 18.7939 m