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3 years ago

Find the HCF of the following byPime factorisation.a) 72,54,27b) 24, 16, 36

Mathematics

2 answers:

erik [133]3 years ago

8 0

Answer:

a.9

b.4

Step-by-step explanation:

Hope it helps u....

Evgen [1.6K]3 years ago

5 0

Answer:

a) 9

b) 4

Step-by-step explanation:

PLS GIVE BRAINLIEST

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makkiz [27]

Answer: 55 cubic units

Step-by-step explanation:

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3 years ago

Given ⊙A, an angle ∠CDB is inscribed with ∡CDB=43°. A second angle, ∠CEB, is inscribed. Find ∡CEB.

wel

180 Fosho Fosho I think

5 0

3 years ago

Sally had 10 peaches left at are roadside fruit stand. she went to the Orchard and picked more peaches to stock up at the stand

Diano4ka-milaya [45]

Answer:73-10

Step-by-step explanation:

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3 years ago

1. A farmer is painting his silo. A typical can of paint covers 400 squared meters.

Maksim231197 [3]

Answer:

1. 6/10 – 2/5 =

Ans: 2/10, which can be reduced to 1/5.

2. If a tank is 5/8 filled with solution, how much of the tank is empty?

Ans: 3/8 of the tank is empty. Since the whole tank would equal 8/8, or 1, and 5/8 of it is filled, then that

means 3/8 of it remains empty.

3. 1/2 x 3/5 x2/3 =

Ans: 6/30, which can be reduced to 1/5.

4. 5/9 ÷ 4/11 =

Ans: 55/36. You cannot reduce this fraction any further.

5. Convert 27/4 to a decimal.

Ans: 6.75. This answer is arrived at by dividing 4 into 27.

6. Convert 0.45 to a fraction.

Ans: 45/100, which can be reduced to 9/20.

7. 4.27 x 1.6 =

Ans: 6.832

8. 6.5 ÷ 0.8 =

Ans: 8.125

9. 12 + 4.52 + 245.621 =

Ans: 262.141

Step-by-step explanation:

3 0

3 years ago

part 2. Find the value of the trig function indicated, use for that Pythagorean theorem to find the third side if you need it.

andreev551 [17]

Answer: $\bold{5)\ \cos \theta=\dfrac{\sqrt{11}}{6}\qquad 6)\ \tan \theta =\dfrac{8}{17}\qquad 7)\ \cos \theta = \dfrac{4}{3}\qquad 8)\ \cos \theta = \dfrac{\sqrt{10}}{10}}$

<u>Step-by-Step Explanation:</u>

Pythagorean Theorem is: a² + b² = c² , <em>where "c" is the hypotenuse</em>

$5)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{3\sqrt{11}}{18}\quad \rightarrow \large\boxed{\dfrac{\sqrt{11}}{6}}$

Note: (15)² + (3√11)² = hypotenuse² → hypotenuse = 18

$6)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{8}{17}\quad =\large\boxed{\dfrac{8}{17}}$

Note: 8² + 15² = hypotenuse² → hypotenuse = 17

$7)\ \tan \theta=\dfrac{\text{side opposite to}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{20}{15}\quad \rightarrow \large\boxed{\dfrac{4}{3}}$

Note: hypotenuse not needed for tan

$8)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{2}{2\sqrt{10}}\quad =\large\boxed{\dfrac{\sqrt{10}}{10}}$

Note: 2² + 6² = hypotenuse² → hypotenuse = 2√10

8 0

3 years ago

Find the HCF of the following byPime factorisation.a) 72,54,27b) 24, 16, 36​

Find the HCF of the following byPime factorisation.a) 72,54,27b) 24, 16, 36