Answer:
8% probability that he or she actually has the disease
Step-by-step explanation:
We use the Bayes Theorem to solve this question.
Bayes Theorem:
Two events, A and B.

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.
If a randomly chosen person is given the test and the test comes back positive for conditionitis, what is the probability that he or she actually has the disease?
This means that:
Event A: Test comes back positive.
Event B: Having the disease.
Test coming back positive:
2% have the disease(meaning that P(B) = 0.02), and for those, the test comes positive 98% of the time. This means that 
For the 100-2 = 98% who do not have the disease, the test comes back positive 100-77 = 23% of the time.
Then

Finally:

8% probability that he or she actually has the disease
7.8 = 0.65x
x = 100/65 * 78/10
x = 10/5 * 6
x = 12
Answer:
The answer is A. x + 5, y - 2
Step-by-step explanation:
The answer is A because you would move the block 5 spaces to the right and 2 spaces down.
Hope this helps!
Since lines a and c are parallel and we are given that c is perpendicular to b, we can infer that b is also perpendicular to a.
So, a and b are perpendicular, the angle formed by these lines should be 90.
Hence, angle 2 is 90.
Hope this helps :)
Number one is 13.2 now hold up while I do the rest