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2 years ago

5

Which figure shows a reflection of pre-image QRS over the line t?

1 answer:

il63 [147K]2 years ago

7 0

Answer:

Which point would map onto itself after a reflection across the line y = -x? ... What is the pre-image of vertex A' if the image shown on the graph was created by a reflection across the ... A triangle has vertices at R(1, 1), S(-2, -4), and T(-3, -3). ... Which shows the image of quadrilateral ABCD after the transformation R0, 90°? a.

Step-by-step explanation:

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2 years ago

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2 years ago

I need help with this as soon as possible!

Kay [80]

Answer:

1. -3/6 is negative, because it descends by 3 and goes over by 6.

2. My first answer literally gives the keyword negative, therefore it's a negative line because it has a <em>negative slope</em>.

1. -8/0 is undefined, because there is a rise but there is no run, which also means that it's a:

2. vertical line

1. -5/-10 simplifies to 5/10 or 1/2, which is positive because it rises by 5(or 1) and runs over by 10(or 2).

2. Thus, this means that it's a positive line since it has a <em>positive slope</em>.

1. 0/-2 is zero, because when you actually solve the equation it'll equal 0.

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1 year ago

Show that if u+v and u-v are orthognal, then the vectors u and v must have the same length.

pashok25 [27]

Answer with Step-by-step explanation:

We are given that

u+ v and u-v are orthogonal

We have to prove that u and v must have the same length.

When two vector a and b are orthogonal then

$a\cdot b=0$

By using the property

$(u+v)\cdot (u-v)=0$

We know that

$(a+b)\cdot (a-b)=\mid a\mid^2-\mid b\mid^2$

$\mid u\mid ^2-\mid v\mid^2=0$

$\mid u\mid^2=\mid v\mid^2$

Magnitude is always positive

When power of base on both sides are equal then base will be equal

Therefore,

$\mid u\mid=\mid v\mid$

Hence, the length of vectors u and v must have the same length.

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3 years ago