<span>a.The graph of f(x)= x^2 is widened</span>
My guess is before the current date but not sure hope that helped and sorry I could not do more and always good luck
Answer:0.0081 or 0.81%
Step-by-step explanation:
The required probability is P(3,5,0.1)= C5 3 * p^3*q^2, where
C5 3= 5!/3/2=4*5/2=10
p is the probability that one randomly selected calculator is defective= 10%=0.1
q is the probability that one randomly selected calculator is non-defective.
q=1-p=1-0.1=0.9
So P(3,5,0.1)= 10*0.1^3*0.9^2=0.01*0.81=0.0081
Answer:
The answer is 12.36
Step-by-step explanation:
I just did the assignment and guessed and got them wrong and it said this is the right answer so yeah.
You're welcome!! :D
