Answer:
Numbers are 28 and -15
Step-by-step explanation:
Mark first number X, and second number Y, then:
x-y=43
and
x+y=13
We get system of two equations. Solve it by add both them together:
x-y+x+y=43+13
2x=56
x=28 we get first number
x+y=13
28+y=13
y=13-28
y=-15
25.74803 would be your answer
Answer:
im sorry what ???
Step-by-step explanation:
i cant draw like that i only have 2 hands :(
Answer: Choice B. k(h(g(f(x))))
For choice B, the functions are k, h, g, f going from left to right.
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Explanation:
We have 4x involved, so we'll need f(x)
This 4x term is inside a cubic, so we'll need g(x) as well.
So far we have
g(x) = x^3
g( f(x) ) = ( f(x) )^3
g( f(x) ) = ( 4x )^3
Then note how we are dividing that result by 2. That's the same as applying the h(x) function

And finally, we subtract 1 from this, but that's the same as using k(x)

This leads to the answer choice B.
To be honest, this notation is a mess considering how many function compositions are going on. It's very easy to get lost. I recommend carefully stepping through the problem and building it up in the way I've done above, or in a similar fashion. The idea is to start from the inside and work your way out. Keep in mind that PEMDAS plays a role.
Answer:
y = 2
Step-by-step explanation:
PQ is a diameter, so arc PQ has a central angle of 180°. Inscribed angle PRQ has a measure half that, or 90°. (An inscribed triangle with one side a diameter is a right triangle.)
Then you can write ...
53y -16 = 90
53y = 106 . . . . . add 16
y = 106/53 = 2 . . . . divide by the coefficient of y
y = 2