Use the distributive property and multiply everything in the parentheses by 14.
Leaving you with.. (70 - 3.5 x 350) + 2 / 4 x 1.
Then reduce the parentheses.
Leaving you with.. ( -1155) + 2 / 4 x 1
Then divide 2 by four.
Leaving you with.. (-1155) + .5
Answer.. -1,154.5
ARea = area of square + area of semicircle
= 26^2 + 0.5pi(13)^2
= 941.46 square inches to nearest hundredth
Answer:
a. The percentage of vehicles who pass through this construction zone who are exceeding the posted speed limit =90.82%
b. Percentage of vehicles travel through this construction zone with speeds between 50 mph and 55 mph= 2.28%
Step-by-step explanation:
We have to find
a) P(X>40)= 1- P(x=40)
Using the z statistic
Here
x= 40 mph
u= 44mph
σ= 3 mph
z=(40-44)/3=-1.33
From the z-table -1.67 = 0.9082
a) P(X>40)=
Probability exceeding the speed limit = 0.9082 = 90.82%
b) P(50<X<55)
Now
z1 = (50-44)/3 = 2
z2 = (55-44)/3= 3.67
Area for z>3.59 is almost equal to 1
From the z- table we get
P(55 < X < 60) = P((50-44)/3 < z < (55-44)/3)
= P(2 < z < 3.67)
= P(z<3.67) - P(z<2)
= 1 - 0.9772
= 0.0228
or 2.28%
Answer:
324 minutes or 5 hours 24 minutes
Step-by-step explanation:
On Tuesday, Saima rode her bike for 52 miles. If it takes Saima 6 minutes to ride each mile, then it takes her
minutes to ride all 52 miles.
Before she rides her bike, Saima warms up for 12 minutes.
Therefore, it takes Saima
minutes to warm up and ride her bike on Tuesday.
Answer:
58 miles/hour
Step-by-step explanation:
Given that the family Christmas gathering has been scheduled at 2:00 p.m.,
and Joshua left the house at 8:00 a.m.
So, the total time available in order to arrive on time to attend the Christmas gathering, t=6 hours
The total distance, Joshua has to travel, d= 348 miles.
As average speed= (total distance)/(total time)
So, the average speed of driving = 348/6=58 miles/hour
Hence, Joshua must drive at an average speed of 58 miles/hour in order to arrive on time.
