Yes the ANSWER is Correct-
On first half life the mass will be 10 gram
On second half life the mass will be 5 gram
On third half life the mass will be 2.5 gram
They tell you to have caution.
Answer:
a) 40 %
b)
c)
Explanation:
For a) we will have to calculate the <u>molar mass</u> of , so the first step is to find the <u>atomic mass</u> of each atom and multiply by the <u>amount of atoms</u> in the molecule.
C => 12*(6) = 72
H => 1*(12) = 12
O => 6*(16) = 96
Molar mass = 180 g/mol
Then we can calculate the percentage by mass:
For b) we have to start with the <u>reaction of glucose</u>:
Then we have to convert the grams of glucose to moles, the moles of glucose to moles of carbon dioxide and finally the moles of carbon dioxide to grams. To do this we have to take into account the<u> following conversion ratios</u>:
-) 180 g of glucose = 1 mol glucose
-) 1 mol glucose = 6 mol carbon dioxide
-) 1 mol carbon dioxide = 44 g carbon dioxide
For C, we have to start with the conversion from grams of glucose to moles, the moles of glucose to moles of oxygen and finally the moles of oxygen to molecules. To do this we have to take into account the <u>following conversion ratios</u>:
-) 180 g of glucose = 1 mol glucose
-) 1 mol glucose = 6 mol oxygen
-) 1 mol oxygen = 6.023x10^23 molecules of O2
6.50 x [10]^{2} will be the answer because you have to move the decimal to ex 6.50 instead of 00.650
The question is incomplete, here is the complete question:
A chemistry student needs 10.00 g of isopropenylbenzene for an experiment. She has available 120. g of a 42.7 % w/w solution of isopropenylbenzene in carbon tetrachloride. Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button.
Round the answer to 3 significant digits.
<u>Answer:</u> The mass of solution that the student should use is 23.4 grams
<u>Explanation:</u>
We are given:
42.7 % (w/w) solution of isopropenylbenzene.
This means that 42.7 grams of isopropenylbenzene is present in 100 grams of solution.
To calculate the mass of solution when 10.00 g of isopropenylbenzene is needed, we apply unitary method:
For 42.7 grams of isopropenylbenzene, the amount of solution needed is 100 grams
So, for 10.00 grams of isopropenylbenzene, the amount of solution needed will be =
Hence, the mass of solution that the student should use is 23.4 grams