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ludmilkaskok [199]

4 years ago

10

1. An atom that has an outer shell that is NOT full is (more likely OR less likely) to be reactive than an atom that has a full

outer shell.

1 answer:

Simora [160]4 years ago

5 0

It would be more likely because it is considered unstable more reactive.

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Zolol [24]

There's 6 because it says CH(3)F which means theres three hydrogen atoms in one, which tells us there's six in two

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3 years ago

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Tijuan mixed a solid and a liquid together in a beaker

Nutka1998 [239]

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5 0

3 years ago

When 2.714 g of AX (s) dissolves in 127.4 g of water in a coffee-cup calorimeter the temperature rises from 23.3 °C to 37.1 °C.

MakcuM [25]

Answer : The enthalpy change for the solution is 166.34 kJ/mol

Explanation :

First we have to calculate the enthalpy change of the reaction.

Formula used :

$\Delta H=mC\Delta T\\\\\Delta H=mC(T_2-T_1)$

where,

$\Delta H$ = change in enthalpy = ?

C = heat capacity of water = $4.18J/g.K$

m = total mass of sample = 2.174 + 127.4 = 129.6 g

$T_1$ = initial temperature = $23^oC=273+23=296K$

$T_2$ = final temperature = $37.1^oC=273+37.1=310.1K$

Now put all the given values in the above expression, we get:

$\Delta H=mC(T_2-T_1)$

$\Delta H=129.6g\times 4.18J/g.K\times (310.1-296)K=7638.36J$

Now we have to calculate the moles of AX added to water.

$\text{ Moles of }AX=\frac{\text{ Mass of }AX}{\text{ Molar mass of }AX}=\frac{2.714g}{59.1097g/mole}=0.04592moles$

Now we have to calculate the enthalpy change for the solution.

As, 0.04592 moles releases heat = 7638.36 J

So, 1 moles releases heat = $\frac{7638.36}{0.04592}=166340.59J=166.34kJ$

Therefore, the enthalpy change for the solution is 166.34 kJ/mol

7 0

3 years ago

If the adoms dont work are they dead

Aleks [24]

Answer: no

Explanation:

Atoms are not and have never been alive so they can't be considered dead. they simply do not meet any reasonable of life, primarily because they are not complex.

8 0

2 years ago