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dalvyx [7]
4 years ago
12

The ideal temperature inside a refrigerator is 37*5F plus or minus 3.5*F. Set up and solve an absolute value equation to find th

e high and low limits of the range of temperatures. Show your work.
Mathematics
1 answer:
kicyunya [14]4 years ago
4 0

Answer:

|T -37.5| \leq 3.5

And using properties of absolute value we got:

-3.5 \leq T-37.5 \leq 3.5

And adding 37.5 on both sides is given by:

-3.5+37.5 \leq T \leq 3.5+ 37.5

34 \leq T \leq 41

Step-by-step explanation:

For this case we assume that the ideal temperature is given by T=37.5 F

And for this case we know that the limits within 3.5 F within the ideal temperature so we can write this like that:

|T -37.5| \leq 3.5

And using properties of absolute value we got:

-3.5 \leq T-37.5 \leq 3.5

And adding 37.5 on both sides is given by:

-3.5+37.5 \leq T \leq 3.5+ 37.5

34 \leq T \leq 41

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8 0
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1.A clown made 3 times as many balloon hats as balloon dogs. He made 4 more balloon dogs than balloon swords.Write an algebraic
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7 0
4 years ago
Find the x and y intercepts of the quadratic equation<br> f(x)=-x^2+4x-4
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<u>X - Intercept</u>
f(x) = -x² + 4x - 4
   0 = -x² + 4x - 4
   x = <u>-(4) +/- √((4)² - 4(-1)(-4))</u>
                         2(-1)
   x = <u>-4 +/- √(16 - 16)</u>
                    -2
   x = <u>-4 +/- √(0)
</u>               -2<u>
</u>   x = <u>-4 +/- 0
</u>              -2<u>
</u>   x = <u>-4 + 0</u>      x = <u>-4 - 0</u>  
            -2                 -2
   x = <u>-4</u>             x = <u>-4</u>
         -2                   -2
   x = 2               x = 2

The solution to the problem is {2, 2}, or {2}. The x - intercept of the problem is (2, 0).

<u>Y - Intercept</u>
f(x) = -x² + 4x - 4
f(x) = -(0)² + 4(0) - 4
f(x) = -(0) + 0 - 4
f(x) = -0 + 0 - 4
f(x) = 0 - 4
f(x) = -4

The y - intercept of the problem is (0, -4).
<u />
8 0
4 years ago
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