We take activities of Solids and liquids equal 1. The reason is there concentrations not at all change amount of reactant at equilibrium in the reaction. Hence we don't consider concentrations of pure solids and liquids while writing equilibrium constant.
So for above reaction, equilibrium constant (K) = [Sn^2 +] ^3 x 1 / [Fe^3+]^2 x 1. Ping me if you have any doubts.
Answer:
The excitation energy
Explanation:
Excitation energy is the energy needed move an electron from a lower energy level (usually the ground state) to one of higher energy (an excited state).
Answer:
14 OH⁻(aq) + 2 Cr³⁺(aq) = Cr₂O₇²⁻(aq) + 7 H₂O(l) + 6 e⁻
Explanation:
In order to balance a half-reaction we use the ion-electron method.
Step 1: Write the half-reaction
Cr³⁺(aq) = Cr₂O₇²⁻(aq)
Step 2: Perform the mass balance, adding H₂O(l) and OH⁻(aq) where appropriate
14 OH⁻(aq) + 2 Cr³⁺(aq) = Cr₂O₇²⁻(aq) + 7 H₂O(l)
Step 3: Perform the electric balance, adding electrons where appropriate
14 OH⁻(aq) + 2 Cr³⁺(aq) = Cr₂O₇²⁻(aq) + 7 H₂O(l) + 6 e⁻
The reaction is 2Fe(OH)3 --> Fe2O3 + 3H2O, so the mole ratio of iron (III) hydroxide to water is 2 to 3, or 0.667. That means you need 0.667 moles of iron(III) hydroxide for every mole of water that forms.
<span>You are missing some info. You need the volume of the water vapor. At STP, 1 Liter of gas contains 22.4 moles, so you can find the moles of water vapor once you know the volume of the water vapor in Liters. </span>
<span>Then, mulitply moles of water by 0.667 to find moles of iron (III) hydroxide used. Finally, multiply by the molar mass of iron (III) hydroxide to find the mass in grams.</span>
