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Required five terms of sequence are 19 , 12 , 5 , -2 and -9 .
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Solution:
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Need to find the five terms of the sequence.
Given recursive rule is f(x) = f(x-1) -7
Substituting x = 2 , f(2) = f(2-1)-7
= f(2) = f(1) – 7 ------(1)
Also given that f(2) = 12.
On substituting the given value of f(2) in eq (1) we get
12 = f(1) – 7
f(1) = 12 + 7 = 19
Using given recursive rule and given value of f(2) calculating f(3)
Substituting x = 3 ,
f(3) = f(3-1) – 7
= f(2) – 7
= 12 – 7
= 5
Using given recursive rule and calculated value of f(3) calculating f(4)
Substituting x = 4,
f(4) = f(4-1) – 7
= f(3) – 7
= 5– 7
= -2
Using given recursive rule and calculated value of f(4) calculating f(5)
Substituting x = 5,
f(5) = f(5-1) – 7
= f(4) – 7
= -2– 7
= -9
Hence required five terms of sequence are 19 , 12 , 5 , -2 and -9 .
C is the answer for the problem
This is what I get not sure if the problem on numerator is together if it is then . X^2+(a^2+1) x^2+a^2+1.
-----------------= ----------------- AX+1. Ax+1 Answer: a^2+x^2+1 ---------------- AX+1
If I wrote the actual problem wrong let me know. This is what I understood.
Answer:
D. 4in, 12in
Step-by-step explanation:
Area of triangle = 24in²
Unknown:
Base and height of the triangle = ?
Solution:
The area of a triangle = 
x base x height
From the problem,
base = 
x height
let the base = b
height = h
b = h
h = 3b
Input into the formula of area;
24 = x b x 3b
Mulitply through by 2;
48 = 3b²
b² = 16
b = √16 = 4
So, h = 3b= 3 x 4 = 12in
Answer:
1/3
Step-by-step explanation:
To find the common ratio, take the second term and divide by the first term
9/27 = 1/3
Check by dividing the third term by the second
3/9 = 1/3
and so forth
1/3 = 1/3
etc
The common ratio is 1/3
