All categories

3 years ago

I reallly need help plss -m=5-plssss

Mathematics

1 answer:

antiseptic1488 [7]3 years ago

5 0

Answer:

$4m ^{2} = 4 \times 5 \times 5 = 100$

You might be interested in

When graphing a linear inequality, when can you NOT use (0, 0) as a test point to determine which side of a boundary line to sha

TEA [102]

When the point (0,0) is on the boundary line

8 0

4 years ago

Read 2 more answers

4. For graduation, Diamond was able to buy her first car for $24,000. Her parents gave her a present and made a

s344n2d4d5 [400]

Answer:

$403.15

Step-by-step explanation:

Principal loan amount is the total amount minus down-payment:

$Principal=24000-1000\\\\=23000$

Knowing that $n=12\times 6=72,P=23000, r=7.99\%/12=0.006658$ , the monthly payments can be calculated using the formula:

$M=P[\frac{r(1+r)^n}{(1+r)^n-1}]\\\\=23000\frac{(0.006658(1.006658)^{72}}{1.006658^{72}-1}\\\\=403.15$

Hence, the monthly payment is $403.15

3 0

3 years ago

Select the statement that correctly describes the expression below

Kitty [74]

Answer:

Step-by-step explanation:

The equation is (2x+5)^2.

It can't be A because 2 is the multiplier for only x.

It can't be C because the square is outside of the equation.

It can't be D because again, the square is outside of the equation.

So the only thing left is B.

Hope this helped!

7 0

3 years ago

What is the simplest form of this expression?

Dimas [21]

Answer:

(4-m-1)-5

Remove the bracket

= 4-m-1-5

= -2-m

Hope this helps.

7 0

3 years ago

Four boys weighed themselves in different pairs and alone. The weights of the pairs were 110 kg, 112 kg, 113 kg, 118 kg, 121 kg,

brilliants [131]

The lost pair of weight can be found by subtracting the a known pair from

the total weight leaving the value of the lost pair.

The lost weight of a pair of boys is 120 kg

Reasons:

Let a, b, c, and d represent the weights of the four boys, we have;

The number of ways of selecting pairs (two boys) of boys from a group of

four is given using combination formula as follows;

$_nC_r = \dfrac{n!}{r! \cdot (n - r)!}$

Which gives;

$_4C_2 = \dfrac{4!}{2! \cdot (4 - 2)!} = 6$

₄C₂ = 6

Therefore, the weights of the pairs are;

a + b = 110

a + c = 112

a + d = 113

b + c = 118

b + d = 121

c + d = Lost weight

c + d = Lost weight

a + b + c + d = 230 (given)

Therefore;

The lost weight, c + d = 230 - (a + b)

Which gives;

c + d = 230 - (110) = 120

The lost weight = c + d = 120

The lost weight = 120 kg

Learn more here:

brainly.com/question/12974932

6 0

2 years ago

Read 2 more answers