Answer:
Your answer should be B. Cooled air
Explanation:
Answer:
1.3 rev/s
Explanation:
= Moment of inertia when arms and one leg of the skater is out = 3.5 kgm²
= Moment of inertia when arms and legs of the skater are in = 0.80 kgm²
= Angular speed of skater when arms and legs of the skater are in = 5.5 rev/s
= Angular speed of skater when arms and legs of the skater are out = ?
Using conservation of angular momentum
=
(0.80) (5.5) = (3.5)
= 1.3 rev/s
Answer:
The maximum height reached by the ball is 2.84 m
Explanation:
Given;
initial velocity of the soccer, u = 13 m/s
angle of projection, θ = 35°
The maximum height reached by the ball = ?
Apply the following kinematic equation, to determine the maximum height reached by the ball.
Maximum height (H) is given as;
Therefore, the maximum height reached by the ball is 2.84 m
you need to use hours to make it easy to convert to m/s. Change 15 minutes to hours
Note distance is in km so change the time to hours to get km/hour
1 hour = 60mins so 15 minutes will be 0.25 hours
10/0.25 = 40 km/ hour
To change that to m/second, change km to meters and hour to second
it will be (40x1000) meters /3600seconds
11.1111 m/s
Answer:
P = 2.18 atm
Explanation:
The strategy here here is to use the ideal gas law
PV = nRT
since we know the temperature, volume and the n, the number of moles is mass/MW, and R is the gas constant 0.08205 LatmK⁻¹mol⁻¹:
MW HI = 127.91 gmol⁻¹
P = ( mass / MW ) x R x T / V
P= (50.0 g / 127.91 gmol⁻¹ ) x 0.08205 LatmK⁻¹mol⁻¹ x 340 K/ 5.00 L
P = 2.18 atm
( rounded to three significant figures which is the number of significant figures for temperature, mass and volume )
