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4 years ago

Of these nonmetals, which one is likely to be the least reactive?

Physics

2 answers:

umka21 [38]4 years ago

8 0

Answer:

helium

Explanation:

yarga [219]4 years ago

8 0

Answer:

hope this helps ;) its sulfer

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What happens when infrared hits a shiny surface

saw5 [17]

Will reflect ........

3 0

4 years ago

What is the potential of a 10kg book that is placed on a shelf that is 2.5 meters high

AveGali [126]

Answer:

250 J

Explanation:

U = mgh

U = 10 *10 * 2.5 = 250 J

7 0

4 years ago

Two large parallel conducting plates carrying opposite charges of equal magnitude are separated by 2.20 cm. If the surface charg

bekas [8.4K]

Answer:

$5.3\times 10^3 N/C$

Explanation:

We are given that

Distance between plates=d=2.2 cm= $2.2\times 10^{-2} m$

$1 cm=10^{-2} m$

$\sigma=47nC/m^2=47\times 10^{-9}C/m^2$

Using $1 nC=10^{-9} C$

We have to find the magnitude of E in the region between the plates.

We know that the electric field for parallel plates

$E=\frac{\sigma}{2\epsilon_0}$

$E_1=\frac{\sigma}{2\epsilon_0}$

$E_2=\frac{\sigma}{2\epsilon_0}$

$E=E_1+E_2$

$E=\frac{\sigma}{2\epsilon_0}+\frac{\sigma}{2\epsilon_0}=\frac{\sigma}{\epsilon_0}$

Where $\epsilon_0=8.85\times 10^{-12}C^2/Nm^2$

Substitute the values

$E=\frac{47\times 10^{-9}}{8.85\times 10^{-12}}$

$E=5.3\times 10^3 N/C$

Hence, the magnitude of E in the region between the plates= $5.3\times 10^3 N/C$

5 0

3 years ago

Help me understand why 5G cell phones and cell phone towers do not cause cancer even with prolonged exposure and are not harmful

Nat2105 [25]

Answer:

I'm not really sure as far as cell phone towers, but 5G hasn't published any safety tests, so we don't know for sure whether or not this would be harmful/cancer causing. The lack of evidence in either direction may be why we can't say definitively that it is safe or not harmful. Hope this helps.

Explanation:

7 0

3 years ago

A mass spectrometer is being used to monitor air pollutants. it is difficult, however, to separate molecules with nearly equal m

Fynjy0 [20]

Answer:

The answer is 1250 mm

Explanation:

The path that particles move in the spectrometer is semicircular. Each of the particles has a displacement of twice the radius (2r) from the entrance to where the film is hit. According to the exercise, if the separation between the two molecules is 0.25 mm, then the difference in the radius of the molecules is equal to 0.125 mm. The ratio of mass/radius is equal for molecules, and therefore is equal to:

m = q * B * r / v

m/r = constant

(m/r)CO = (m/r)N = (28.0106 u/r) = (28.0134 u/(r + 0.000125 m))

Clearing and solving r:

r = 1.25 m = 1250 mm

4 0

3 years ago