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Morgarella [4.7K]
3 years ago
14

I need help with this question​

Mathematics
1 answer:
insens350 [35]3 years ago
8 0

Answer:

2

Step-by-step explanation:

I don't think you are asked to prove that these triangles are similar. The diagram leads you to believe that they are. The easiest way to solve this is to take 2 corresponding lines and compare them.

So how do you get from FE to BA

BA / FE = 6/3

BA = 6

FE = 3

BA / FE = 6/3

BA / FE = 2

The scale factor is 2

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-n+(-4)-(-4n)+6<br><br><br> solve
tigry1 [53]

Answer:

3n + 2

Step-by-step explanation:

-n+(-4)-(-4n)+6

= -n -4 +4n +6        [positive plus negative =  negative; ∴  +(-4) = -4

=4n - n +6 - 4                      negative plus negative = positive; ∴ -(-4n) = 4]

now subtract n from 4n and subtract 4 from 6

=3n + 2

                                                                                                       

                             

8 0
3 years ago
Read 2 more answers
Name the property the equation illustrates.
vodomira [7]
Commutative Property of Addition
4 0
2 years ago
Read 2 more answers
An automobile factory,1849 parts are made in 4 hours.what is the average rate at which parts are made per hour?
MAXImum [283]

Answer:

There are 462.25 parts being made per hour

Step-by-step explanation:

<u>Step 1:  Make an equation</u>

An automobile factory, 1849 parts are made in 4 hours.

<em>1849 / 4 = x</em>

<em />

<u>Step 2:  Solve</u>

1849 / 4 = x

<em>462.25 = x</em>

<em />

Answer:  There are 462.25 parts being made per hour

7 0
3 years ago
Read 2 more answers
Bill and George go target shooting together. Both shoot at atarget at the same time. Suppose Bill hits the target withprobabilit
german

Answer: (a) \frac{2}{9}       (b) \frac{6}{41}

Step-by-step explanation:

(a) P( Bill hitting the target) = 0.7        P( Bill not hitting the target) = 0.3

    P( George hitting the target) = 0.4     P(George not hitting the target) = 0.6

Now the chances that exactly one shot hit the target is = 0.7 x 0.6 + 0.4 x 0.3

                                                                                            = 0.54

Chances that George hit the target is = 0.4 x 0.3 = 0.12

So given that exactly one shot hit the target, probability that it was George's shot = \frac{0.12}{0.54} = \frac{2}{9} .

(b) The numerator in the second part would be the same as of (a) part which is 0.12.

The change in the denominator will be that now we know that the target is hit so now in denominator we include the chance of both hitting the target at same time that is 0.4 x 0.7 and the rest of the equation is same as above i.e.

Given that the target is hit,probability that George hit it =                                                 \frac{0.4\times 0.3}{0.7\times 0.6 +0.4\times 0.3+0.4\times 0.7}  = = \frac{6}{41}                                                                        

                                                                                           

6 0
3 years ago
Ashley bought 14 rainbow and balloon stickers for her little sister. The rainbow stickers cost 6 cents apiece and the balloon st
Morgarella [4.7K]

Answer:

Ashley bought 6 rainbow stickers and 8 balloon stickers for her little sister.

Step-by-step explanation:

Let the number of rainbow sticker be x and number of balloon stickers be y.

Cost a single rainbow sticker= 6 cents

Cost a single balloon sticker= 4 cents

Cost a single x rainbow sticker= 6 cents × x

Cost a single y balloon sticker= 4 cents × y

Total number of stickers bought = 14

x + y =14 ..[1]

Total money spend on stickers = 68 cents

6x cents+4y cents=68 cents

6x+4y=68...[2]

Putting value of from [1] into [2];

x = 14 - y

6(14-y)+ 4y=68

84-6y+4y=68

-2y=-16

y=\frac{-16}{-2}=8

x = 14 -y =14 - 8 = 6

Ashley bought 6 rainbow stickers and 8 balloon stickers for her little sister.

3 0
3 years ago
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