<span>Let A be the center of a circle and two angles at the adjacent center AOB and BOC. Knowing the measure of the angle AOB = 120 and the measure BOC = 150, find the measures of the angles of the ABC triangle.
</span>solution
Given the above information;
AC=AB, therefore ABC is an isosceles triangle.
therefore, BAO=ABO=(180-120)/2=30
OAC=OCA=(180-90)/2=45
OBC=BCO=(180-150)/2=15
THUS;
BAC=BAO+OAC=45+30=75
ABC=OBA+CBO=15+30=45
ACB=ACO+BCO=15+45=60
Don’t open the link it’s a hacking business Good luck.
Answer:
8.5
Step-by-step explanation:
The tenth place is the first number to the right of the decimal. It goes tenths, hundredths, thousandths... etc from left to right after the decimal.
Prime numbers are numbers that only have a factor of one and its self.
Answer:
Just pick 2 coins to compare (I mean the directions say compare 2).
Step-by-step explanation:
