v + m = 32 and v = 5 + 2m are the equations that are used to determine m, the number of stuffed animals Mariposa has
Number of stuffed animals Mariposa has is 9 and number of stuffed animals with Veronica is 23
<h3>
<u>Solution:</u></h3>
Let "v" be the number of stuffed animals with Veronica
Let "m" be the number of stuffed animals with Mariposa
Given that,
Together, they have 32 stuffed animals
Therefore,
v + m = 32 --------- eqn 1
Veronica has 5 more than double the number of stutted animals as her friend Mariposa
Therefore,
Number of stuffed animals with Veronica = 5 + 2(number of stuffed animals with Mariposa)
v = 5 + 2m ---------- eqn 2
Thus eqn 1 and eqn 2 can be used to determine m, the number of stuffed animals Mariposa has
Let us solve eqn 1 and eqn 2
Substitute eqn 2 in eqn 1
5 + 2m + m = 32
5 + 3m = 32
3m = 32 - 5
3m = 27
<h3>m = 9</h3>
Substitute m = 9 in eqn 2
v = 5 + 2(9)
v = 5 + 18
<h3>v = 23</h3>
Thus number of stuffed animals Mariposa has is 9 and number of stuffed animals with Veronica is 23
Answer:
not correct
tan 60 = x / 2
square root(3) = x / 2
x = 2 * Square root(3)
= Square root ( 4 * 3) = Square root (12)
10x
8x-2
6x+4
They all simplify
Answer:

Step-by-step explanation:
The area of a sector with measure
in degrees is given by
, where
is the radius of the sector.
What we're given:
Solving, we get:

*Notes:
- units should be in square meters (area)
- the problem does not say whether to round or leave answers in term of pi, so you may need to adjust the answer depending on what your teacher specifically wants
Answer:
The width of the frame must be 12 inches (15in by 12in)
Step-by-step explanation:
Given
See attachment for painting and frame
Required
Determine the dimension of the frame
To do this, we make use of the following scale ratio.

For the painting,

For the frame,

Since she wants to maintain the same ratio; both scale must be the same.
i.e.

Express as fraction


Make w the subject


<em>The width of the frame must be 12 inches i.e. 15in by 12in frame</em>