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Aleonysh [2.5K]
3 years ago
9

8 and 9 please Extra 100 points And brainleist

Mathematics
1 answer:
lesantik [10]3 years ago
5 0

Answer:

9 . (4)

10 . 17

Step-by-step explanation:

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-5 5/8 + 3 1/2<br> A -3 1/8<br> B -2 1/2<br> C -2 1/8<br> D -7/8
lisov135 [29]

Answer: C. -2 1/8

Step-by-step explanation:

<em>-5 - 3 = -2</em>

<em>5/8 - 1/2 = 1/8</em>

<em>-2 1/8</em>

4 0
3 years ago
If using the method of completing the square to solve the quadratic equation x^2 + 9 x + 7 = 0 , which number would have to be a
FinnZ [79.3K]

Answer:

(x+9)^2=53/4

Step-by-step explanation:

6 0
3 years ago
F(x)=-3x+5x^2+8 has_____ roots
nikitadnepr [17]

Answer:12

Step-by-step explanation:

3 0
3 years ago
If A = {4, 7, 10, 13, 17) and B = {3,5, 7, 9), then which of the following statements is true?
stealth61 [152]

Answer:

B

Step-by-step explanation:

hope this helps

6 0
3 years ago
A rare form of malignant tumor occurs in 11 children in a​ million, so its probability is 0.000011. Four cases of this tumor occ
Shkiper50 [21]

Answer:

a) The mean number of cases is 0.14608 cases.

b) The probability that the number of cases is exactly 0 or 1 is 0.990.

c) The probability of more than one case is 0.010

d) No, because the probability of more than one case is very small

Step-by-step explanation:

We can model this problem with a Poisson distribution, with parameter:

\lambda=r*t=0.000011*13,280=0.14608

a) The mean amount of cases is equal to the parameter λ=0.14608.

b) The probability of having 0 or 1 cases is:

P(k=0)=\frac{\lambda^0 e^{-\lambda}}{0!}=\frac{1*0.864}{1} =0.864\\\\ P(k=1)=\frac{\lambda^1 e^{-\lambda}}{0!}=\frac{0.14608*0.864}{1} =0.126\\\\P(k\leq1)=0.864+0.126=0.990

c) The probability of more than one case is:

P(k>1)=1-P(k\leq 1)=1-0.990=0.010

d) The cluster of 4 cases can not be due to pure chance, as it is a very high proportion of cases according to the average rate. Just having more than one case has a probability of 1%.

7 0
3 years ago
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