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alekssr [168]
3 years ago
14

Help me to solve this

Chemistry
1 answer:
Diano4ka-milaya [45]3 years ago
7 0

Answer: The average atomic mass of nitrogen is 14.0066 amu

Explanation:

Mass of isotope N-14 = 14.00307 amu

% abundance of isotope N-14= 99.64% = \frac{99.64}{100}

Mass of isotope N-13 = 15.0001 amu

% abundance of isotope N-13= (0.36)% = \frac{0.36}{100}

Formula used for average atomic mass of an element :

\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})

A=\sum[(14.00307)\times \frac{99.64}{100})+(15.0001)\times \frac{0.36}{100}]]

A=14.0066amu

Therefore, the average atomic mass of nitrogen is 14.0066 amu

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Boron is an exception to the octet rule and can take up to 10 electrons in its valence shell.
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Answer:

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Explanation:

Boron is an exception to the octet rule because it possesses less than eight electrons. Boron has five electrons with three of them being valence electrons and therefore has an incomplete octet. It readily forms compounds in which it has six valence electrons, rather than the usual eight.

Hope that helps.

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3 years ago
The heat index temperature:___________ a. bines air pressure and temperature in a comfort index b. bines relative humidity and t
kvasek [131]

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bines relative humidity and temperature in a comfort index

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The Heat Index temperature measures how hot it feels when humidity is factored with the air temperature.

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6 0
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6 0
3 years ago
Hexokinase iv has a km value that is substantially higher than the km for other hexokinases. what is the significance of this fa
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8 0
3 years ago
In this reaction, what roll does the lead (II) nitrate play when 50.0 mL of 0.100M iron (III) chloride are mixed with 50.0 mL of
Aloiza [94]

Answer: The roll of lead (II) nitrate is that it is a limiting reactant of the reaction.

Solution : Given,

Molarity of FeCl_3 = 0.1 M

Volume of FeCl_3 = 50.0 ml = 0.05 L     (1 L = 1000 ml)

Molarity of Pb(NO_3)_2 = 0.1 M

Volume of Pb(NO_3)_2 = 50.0 ml = 0.05 L

First we have to calculate the moles of FeCl_3 and Pb(NO_3)_2.

\text{ Moles of }FeCl_3=\text{ Molarity}\times \text{ Volume in L}

\text{ Moles of }FeCl_3=(0.100M)\times (0.05L)=0.005moles

\text{ Moles of }Pb(NO_3)_2=\text{ Molarity}\times \text{ Volume in L}

\text{ Moles of }Pb(NO_3)_2=(0.100M)\times (0.05L)=0.005moles

The balanced chemical reaction is,

2FeCl_3+3Pb(NO_3)_2\rightarrow 2Fe(NO_3)_3+3PbCl_2

From the balanced chemical equation, we conclude that

3 moles of lead nitrate react with 2 moles of ferric chloride.

Thus 0.005 moles of lead nitrate react with =\frac{2}{3}\times 0.005=0.0033 moles of ferric chloride.

Moles of ferric chloride will be left unreacted = 0.005 - 0.0033 =0.0017 moles

Limiting reagent is the reagent in the reaction which limits the formation of product.

Excess reagent is the reagent in the reaction which is in excess and thus remains unreacted.

Therefore, in the given reaction, lead nitrate is the limiting reagent and ferric chloride is the excess reagent.

7 0
3 years ago
Read 2 more answers
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