2 years ago

:

Chemistry

1 answer:

Mkey [24]2 years ago

5 0

1)How many molecules are
there in 2.3 grams of NH
SO.?
Answer:

1.69 x 10^22

You might be interested in

What is kinetic energy related to? heat position motion electricity

Anna35 [415]

The Answer Should Be Motion

8 0

3 years ago

Read 2 more answers

If the distance between London and New York is 3600 miles, how long would you

Tju [1.3M]

Answer:

3 hours

Explanation:

s=d/t

1200=3600/t

3600/1200=t

t=3

3 0

3 years ago

Which of the following is an anion? A. O^2- C. Al^3+ D. H

kifflom [539]

The correct answer is A. O^2-

6 0

3 years ago

2-phosphoglycerate(2PG) is converted to phosphoenolpyruvate (PEP) by the enzyme enolase. The standard free energy change(deltaGo

pogonyaev

Answer:

The correct option is: (D) -2.4 kJ/mol

Explanation:

Chemical reaction involved: 2PG ↔ PEP

Given: The standard Gibb's free energy change: ΔG° = +1.7 kJ/mol

Temperature: T = 37° C = 37 + 273.15 = 310.15 K (∵ 0°C = 273.15K)

Gas constant: R = 8.314 J/(K·mol) = 8.314 × 10⁻³ kJ/(K·mol) (∵ 1 kJ = 1000 J)

Reactant concentration: 2PG = 0.5 mM

Product concentration: PEP = 0.1 mM

Reaction quotient: $Q_{r} =\frac{\left [ PEP \right ]}{\left [ 2PG \right ]} = \frac{0.1 mM}{0.5 mM} = 0.2$

To find out the Gibb's free energy change at 37° C (310.15 K), we use the equation:

$\Delta G = \Delta G^{\circ } + 2.303 R T log Q_{r}$

$\Delta G = 1.7 kJ/mol + [2.303 \times (8.314 \times 10^{-3} kJ/(K.mol))\times (310.15 K)] log (0.2)$

$\Delta G = 1.7 + [5.938] \times (-0.699) = 1.7 - 4.15 = (-2.45 kJ/mol)$

Therefore, the Gibb's free energy change at 37° C (310.15 K): ΔG = (-2.45 kJ/mol)

4 0

3 years ago

What is the mass in grams of one mole of many of any substance known as

OLEGan [10]

The molecular weight of the substance.

7 0

3 years ago