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Rudik [331]
3 years ago
9

In the reaction Zn H 2SO 4→ ZNSO4 + H2, which, if any element is oxidized

Chemistry
1 answer:
Anika [276]3 years ago
7 0

Answer:

hope this helps!!!!!

Explanation:

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1. How many moles of LiBr are present in 100 mL of 1.25M LIBr solution?
Svet_ta [14]

Answer:

https://www.webassign.net/question_assets/wertzcams3/appendix.pdf

7 0
3 years ago
What is the concentration, in m/v percent, of a solution prepared from 50 g NaCl and 2.5 L of solution?
Serjik [45]
When we convert the given mass in grams and volume in liters to m/v percent, we recall that m/v percent is expressed as grams/100 milliliters. In this case the expression becomes (50 grams/ 2500 L)*(0.1L/100ml), that is equal to 0.002 grams/ 100 mL. Hence the the concentration is equal to 0.2 m/v percent.
4 0
3 years ago
How much CaCO3 would have to be decomposed to produce 247 g of CaO
vovangra [49]

441 g CaCO₃ would have to be decomposed to produce 247 g of CaO

<h3>Further explanation</h3>

Reaction

Decomposition of CaCO₃

CaCO₃ ⇒ CaO + CO₂

mass CaO = 247 g

mol of CaO(MW=56 g/mol) :

\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{247}{56}\\\\mol=4.41

From equation, mol ratio CaCO₃ : CaO = 1 : 1, so mol CaO :

\tt \dfrac{1}{1}\times 4.41=4.41

mass CaCO₃(MW=100 g/mol) :

\tt mass=mol\times MW\\\\mass=4.41\times 100\\\\mass=441~g

6 0
3 years ago
When a capacitor has a potential difference between the plates it is said to be ? . one plate has an excess of electrons and one
Ede4ka [16]

When a capacitor has a potential difference between the plates it is said to be Constant.

Both plates have different charge which signifies that one has higher potential than the other.

Therefore, when we join them in parallel, charge will flow from higher to lower. and it continued to flow until equilibrium (the entire process took only a few seconds), indicating that the potential remains constant.

To learn more about constant potential difference in capacitor visit:

brainly.com/question/3480856

#SPJ4

6 0
1 year ago
Determine the mass of 2.75 moles of CaSO4. Record your work and your answer.
maw [93]

Explanation:

RFM \:  = 160 \: g \\ 1 \: mole \: weighs \: 160 \: g \\ 2.75 \: moles \: weighs \:  \frac{2.75 \times 160}{1} g \\  = 440 \: g

6 0
3 years ago
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