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Setler79 [48]
2 years ago
13

1+1= 5 2 3 1 help me plz

Mathematics
2 answers:
EleoNora [17]2 years ago
7 0

Answer:

2 haha

Step-by-step explanation:

lawyer [7]2 years ago
5 0

Answer:

2

Step-by-step explanation:

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What is the relationship between \blueD{\angle a}∠astart color #11accd, angle, a, end color #11accd and \greenD{\angle b}∠bstart
Elza [17]

Answer:

Complementary angles.

Step-by-step explanation:

Notice that \angle a=\angle AXY, \angle b = \angle YXB  and \angle BXC = 90\°, by given.

\angle AXB = \angle AXY + \angle YXB, by sum of angles.

\angle AXB + \angle BXC = 180\°, by supplementary angles definition.

\angle AXB + 90\° = 180\°\\\angle AXB = 180\° - 90\°\\\angle AXB = 90\°

Which means,

\angle AXB = \angle AXY + \angle YXB = 90\°

Therefore,\angle a + \angle b = 90\°, in other words, angles a and b are complementary by definition.

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2 years ago
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A store pays $10 for a bracelet,and the markup is 115%. A customer will also pay a 5 and 1/2% sales tax.What will be the total c
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3 years ago
1. Write the slope-intercept form of the equation that passes through the point (0, 1) and is parallel to the line y = 3x - 5
gregori [183]

Answer:

y = 3x + 1

Step-by-step explanation:

If two lines are parallel to each other, they have the same slope.

The first line is Y = 3X - 5. Its slope is 3. A line parallel to this one will also have a slope of 3.

Plug this value (3) into your standard point-slope equation of y = mx + b.

y = 3x + b

To find b, we want to plug in a value that we know is on this line: in this case, it is (0, 1). Plug in the x and y values into the x and y of the standard equation.

1 = 3(0) + b

To find b, multiply the slope and the input of x (0)

1 = 0 + b

Now, add 0 to both sides to isolate b.

1 = b

Plug this into your standard equation.

y = 3x + 1

This equation is parallel to your given equation (y = 3x - 5) and contains point (0, 1)

Hope this helps!

3 0
3 years ago
Rory's battery was full at 6:00 a.M, or t = 0. Which times could Rory's phone have been plugged into the charger? Select three o
Taya2010 [7]

Complete question:

Rory records the percentage of battery life remaining on his phone throughout a day. The graph represents the percentage of battery life remaining after a certain number of hours.

Rory’s battery was full at 6:00 a.m, or t = 0. Which times could Rory's phone have been plugged into the charger? Select three options.

12:00 p.m.

3:00 p.m.

5:00 p.m.

8:00 p.m.

11:00 p.m.

The graph is attached

Answer:

3:00 p.m

5:00 p.m

11:00 p.m

Step-by-step explanation:

From the graph, there are rise times, fall times and there are times the movement is steady (no rise or fall).

The rise time represents the time the phone was plugged. The fall time represents when the charger has been unplugged so the battery level starts depreciating. When it is constant, it means the battery level is at 100 but the charger is still connected to the phone.

We are told at initial condition, time was 6 a.m (t = 0). To get the exact time, we are to add the initial condition, i.e 6

From the graph, the times the phone could have been plugged are 8:00 to 12:00 hrs and 16:00 to 20:00 hrs.

Converting from 24 hr to 12 hr time, we have:

6 + 8hrs = 14:00 = 2:00 p.m

6 + 9hrs = 15:00 = 3:00 p.m

6 + 10 hrs = 16:00 = 4:00 p.m

6 + 11 hrs = 17:00 = 5:00 p.m

6 + 12 hrs = 18:00 = 6:00 p.m

6 + 16 hrs = 22:00 = 10:00 p.m

6 + 17 hrs = 23:00 = 11:00 p.m

6 + 18 hrs = 00:00 = 12:00 am

6 + 19 = 1 : 00 = 1:00 a.m

6 + 20 = 2:00 = 2:00 a.m

From the options given in the question, we have:

3:00 p.m; 5:00 p.m; 11:00 p.m

Therefore, times could Rory's phone have been plugged into the charger are:

3:00 p.m

5:00 p.m

11:00 p.m

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