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2 years ago

1+1= 5 2 3 1 help me plz

Mathematics

2 answers:

EleoNora [17]2 years ago

7 0

Answer:

2 haha

Step-by-step explanation:

lawyer [7]2 years ago

5 0

Answer:

Step-by-step explanation:

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The polynomial of degree 5, P ( x ) has leading coefficient a=1, has roots of multiplicity 2 at x = 3 and x = 0 , and a root of

ser-zykov [4K]

Answer:

$p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}$ , for $r_{1} = 0$

Step-by-step explanation:

The general form of quintic-order polynomial is:

$p_{5}(t) = a\cdot x^{5} + b\cdot x^{4} + c\cdot x^{3} + d\cdot x^{2} + e \cdot x + f$

According to the statement of the problem, the polynomial has the following roots:

$p_{5} (t) = (x - r_{1})\cdot (x-3)^{2}\cdot x^{2} \cdot (x+1)$

Then, some algebraic handling is done to expand the polynomial:

$p_{5} (t) = (x - r_{1}) \cdot (x^{3}-6\cdot x^{2}+9\cdot x) \cdot (x+1)\\p_{5} (t) = (x - r_{1}) \cdot (x^{4}-5\cdot x^{3} + 3 \cdot x^{2} + 9 \cdot x)$

$p_{5} (t) = x^{5} - (5+r_{1})\cdot x^{4} + (3 + 5\cdot r_{1})\cdot x^{3} +(9-3\cdot r_{1})\cdot x^{2} - 9 \cdot r_{1}\cdot x$

If $r_{1} = 0$ , then:

$p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}$

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2 years ago

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Snezhnost [94]

Answer:

Step-by-step explanation:

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2 years ago

Through:(-1,0), perp. to y = x - 4

Yakvenalex [24]

Answer:

Step-by-step explanation:

0= ±4

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3 years ago

How many terms does the following polynomial have? 3x2+4x+2 A. 4 B. 5 C. 3 D. 1

IrinaVladis [17]

I’d say three because there are three main parts to the polynomial separated by plus signs

4 0

2 years ago

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Factor x2 − 7x + 8. (x + 8)(x − 1) Prime (x − 8)(x − 1) (x + 8)(x + 1)

evablogger [386]

Answer:

Prime

Step-by-step explanation:

The roots are irrational. (If they were rational, they would be factors of 8.) As a consequence, the expression has no factoring in integers, making it prime.

_____

Roots are (7±√(7²-32))/2 = 3.5±√4.25.

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2 years ago

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