Answer:
r = i + j + (-2/3)(3i - j)
Step-by-step explanation:
Vector Equation of a line - r = a + kb ; where r is the resultant vector of adding vector a and vector b and k is a constant
if a = i + j ; b = t(3i - j) and r = -i +s(j)
for this to be true all the vector components must be equal
summing i 's
i + 3ti = -i; then t = -2/3
j - tj = sj; then s = 1-t; substitue t; s=1+2/3 = 5/3
so r = i + j + (-2/3)(3i - j) which will symplify to -i + 5/3j
Remember
the deritivive of f(x)/g(x)=(f'(x)g(x)-g'(x)f(x))/((g(x))^2)
deritivive of lnx is 1/x
derivitive of t^2=2t
so

=

=
1287x + 342 +(-198x + 2106) i