Answer:
1. Consistent equations
x + y = 3
x + 2·y = 5
2. Dependent equations
3·x + 2·y = 6
6·x + 4·y = 12
3. Equivalent equations
9·x - 12·y = 6
3·x - 4·y = 2
4. Inconsistent equations
x + 2 = 4 and x + 2 = 6
5. Independent equations
y = -8·x + 4
8·x + 4·y = 0
6. No solution
4 = 2
7. One solution
3·x + 5 = 11
x = 2
Step-by-step explanation:
1. Consistent equations
A consistent equation is one that has a solution, that is there exist a complete set of solution of the unknown values that resolves all the equations in the system.
x + y = 3
x + 2·y = 5
2. Dependent equations
A dependent system of equations consist of the equation of a line presented in two alternate forms, leading to the existence of an infinite number of solutions.
3·x + 2·y = 6
6·x + 4·y = 12
3. Equivalent equations
These are equations with the same roots or solution
e.g. 9·x - 12·y = 6
3·x - 4·y = 2
4. Inconsistent equations
Inconsistent equations are equations that are not solvable based on the provided set of values in the equations
e.g. x + 2 = 4 and x + 2 = 6
5. Independent equations
An independent equation is an equation within a system of equation, that is not derivable based on the other equations
y = -8·x + 4
8·x + 4·y = 0
6. No solution
No solution indicates that the solution is not in existence
Example, 4 = 2
7. One solution
This is an equation that has exactly one solution
Example 3·x + 5 = 11
x = 2
Answer:
x=4
Step-by-step explanation:
tangent lines from the same point to a circle are congruent in length, so we can say that
5x+8 = 8x-4
5x -5x +8 = 8x - 5x -4
8 = 3x - 4
8+4 = 3x -4 + 4
3x = 12
3x/3 = 12/3
x=4
Lets look at the number. 76.78. In each of the different place holders the number is higher than 5. Lets do some examples. 74 rounded to the nearest whole number is going to be 70. 76 rounded to the whole number will be 80. The .78 in your question also contributes.
Answer: 80
Answer:
<h2>Net proceed= s-0.98nd-11</h2>
Step-by-step explanation:
Given that the shares cost $d
n shares will be =$dn
paid 2% commission to her broker= (2/100)*nd= 0.02nd
sold the share for $s
paid a fee of $11
Her net proceeds algebraically will be
Net proceed= s-nd-11-0.02nd
collect like terms
Net proceed= s-(nd-0.02nd)-11
Net proceed= s-0.98nd-11
