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padilas [110]
3 years ago
14

bill spent $19 at starbucks on a coffee and some cookies. if the coffee cost $5 each cookie cost $2, how many cookies did he buy

?
Mathematics
1 answer:
Nataliya [291]3 years ago
6 0

Answer:

this is easy. we know that he spent $19 total, 1 coffee that costed $5, and that each cookie costs $2. all you have to do is subtract 5 from 19 and divide the remaining amount of money (14) by 2. this makes 7 the amount of cookies Bill bought.

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Find the % of change. Original price: $185 New price: $160
mojhsa [17]

Answer:

-13.51

Step-by-step explanation:

work out the difference (increase) between the two numbers you are comparing. Then: divide the increase by the original number and multiply the answer by 100. % increase = Increase ÷ Original Number × 100.,


so, -13.51

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2 years ago
Construct three parallel lines. Then construct two arbitrary non parallel transversal of the parallel lines. Make sure that the
zzz [600]

The image lines constructed are called parallel lines. They are parallel because  they are all equidistant to each other at every point and at no point between any of the lines will there be an intersection of the three lines.

<h3>What does it mean for two or more lines to be equidistant from each other?</h3>

Equidistance is simply another word for equal in distance. That is, parallel lines maintain equal distance from each other at all points along them.

See the attached construction as well as more insights about parallel lines from the link below.

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2 years ago
PLEASE HELP QUICKLY
andreev551 [17]

Answer:

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Step-by-step explanation:

4 0
3 years ago
Connor has 3/8 of a gallon of cherry soda, 3/8 of a gallon of grape soda, 3/8 of a gallon of lemon soda. How much soda, in gallo
V125BC [204]

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7 0
3 years ago
A surveyor leaves her base camp and drives 42km on a bearing of 032degree she then drives 28km on a bearing of 154degree,how far
ValentinkaMS [17]

Answer:

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

Step-by-step explanation:

The final position of the surveyor is represented by the following vectorial sum:

\vec r = \vec r_{1} + \vec r_{2} + \vec r_{3} (1)

And this formula is expanded by definition of vectors in rectangular and polar form:

(x,y) = r_{1}\cdot (\cos \theta_{1}, \sin \theta_{1}) + r_{2}\cdot (\cos \theta_{2}, \sin \theta_{2}) (1b)

Where:

x, y - Resulting coordinates of the final position of the surveyor with respect to origin, in kilometers.

r_{1}, r_{2} - Length of each vector, in kilometers.

\theta_{1}, \theta_{2} - Bearing of each vector in standard position, in sexagesimal degrees.

If we know that r_{1} = 42\,km, r_{2} = 28\,km, \theta_{1} = 32^{\circ} and \theta_{2} = 154^{\circ}, then the resulting coordinates of the final position of the surveyor is:

(x,y) = (42\,km)\cdot (\cos 32^{\circ}, \sin 32^{\circ}) + (28\,km)\cdot (\cos 154^{\circ}, \sin 154^{\circ})

(x,y) = (35.618, 22.257) + (-25.166, 12.274)\,[km]

(x,y) = (10.452, 34.531)\,[km]

According to this, the resulting vector is locating in the first quadrant. The bearing of the vector is determined by the following definition:

\theta = \tan^{-1} \frac{10.452\,km}{34.531\,km}

\theta \approx 16.840^{\circ}

And the distance from the camp is calculated by the Pythagorean Theorem:

r = \sqrt{(10.452\,km)^{2}+(34.531\,km)^{2}}

r = 36.078\,km

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

5 0
3 years ago
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