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NNADVOKAT [17]
3 years ago
10

In two common species of flowers, A and B, the proportions of flowers that are blue are  and  , respectively. Suppose that ind

ependent random samples of 50 species-A flowers and 100 species-B flowers are selected. Let  be the sample proportion of blue species-A flowers and  be the sample proportion of blue species-B flowers. What is the mean of the sampling distribution of 
Mathematics
1 answer:
Juliette [100K]3 years ago
4 0

Answer:

Pa - Pb

Step-by-step explanation:

The mean of the distribution of sample differences will always be the difference between the population proportion, That is ; Pa - Pb ; This is because according to the central limit theorem which says the sampling distribution of sample means approaches a normal distribution as sample size gets larger irrespective if the shape of the Population distribution. Hence, the distribution of sample differences will follow a normal distribution and the mean will Hence be the difference in the population mean.

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In the past, the mean running time for a certain type of flashlight has been 9.2 hours. The manufacturer has introduced a change
ELEN [110]

Answer:

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Step-by-step explanation:

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An order of luxury watch parts is shipped from spain to an assembly plant in the uniited states. The package is weighed before s
Paladinen [302]

Answer:

A. 89.07

Step-by-step explanation:

A kilogram = 2.20462

40.4 kilograms = 40.4 X 2.20462

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3 years ago
Solve the following using Substitution method<br> 2x – 5y = -13<br><br> 3x + 4y = 15
Digiron [165]

\huge \boxed{\mathfrak{Question} \downarrow}

Solve the following using Substitution method

2x – 5y = -13

3x + 4y = 15

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

\left. \begin{array}  { l  }  { 2 x - 5 y = - 13 } \\ { 3 x + 4 y = 15 } \end{array} \right.

  • To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

2x-5y=-13, \: 3x+4y=15

  • Choose one of the equations and solve it for x by isolating x on the left-hand side of the equal sign. I'm choosing the 1st equation for now.

2x-5y=-13

  • Add 5y to both sides of the equation.

2x=5y-13

  • Divide both sides by 2.

x=\frac{1}{2}\left(5y-13\right)  \\

  • Multiply \frac{1}{2}\\ times 5y - 13.

x=\frac{5}{2}y-\frac{13}{2}  \\

  • Substitute \frac{5y-13}{2}\\ for x in the other equation, 3x + 4y = 15.

3\left(\frac{5}{2}y-\frac{13}{2}\right)+4y=15  \\

  • Multiply 3 times \frac{5y-13}{2}\\.

\frac{15}{2}y-\frac{39}{2}+4y=15  \\

  • Add \frac{15y}{2} \\ to 4y.

\frac{23}{2}y-\frac{39}{2}=15  \\

  • Add \frac{39}{2}\\ to both sides of the equation.

\frac{23}{2}y=\frac{69}{2}  \\

  • Divide both sides of the equation by 23/2, which is the same as multiplying both sides by the reciprocal of the fraction.

\large \underline{ \underline{ \sf \: y=3 }}

  • Substitute 3 for y in x=\frac{5}{2}y-\frac{13}{2}\\. Because the resulting equation contains only one variable, you can solve for x directly.

x=\frac{5}{2}\times 3-\frac{13}{2}  \\

  • Multiply 5/2 times 3.

x=\frac{15-13}{2}  \\

  • Add -\frac{13}{2}\\ to \frac{15}{2}\\ by finding a common denominator and adding the numerators. Then reduce the fraction to its lowest terms if possible.

\large\underline{ \underline{ \sf \: x=1 }}

  • The system is now solved. The value of x & y will be 1 & 3 respectively.

\huge\boxed{  \boxed{\bf \: x=1, \: y=3 }}

8 0
2 years ago
Carl is raising money for his football team. He is selling chocolate bars for $1.50 each and cookies for $2. He sold all 20 of h
stich3 [128]

Answer:

Carl has to sell at least 8 cookies.

c\geq 7.5

Step-by-step explanation:

Carl gets \$1.50 by selling 1 chocolate bar.

Earning from chocolate bars:

Total\ chocolate\ bar=20\\\\Earning\ from\ one\ chocolate\ bar=\$1.50\\\\Total\ earning\ from\ chocolate\ bar=Total\ chocolate\ bar\times cost\ of\ 1\ chocolate\ bar=20\times 1.5=\$30

Earning From cookies:

Let\ total\ number\ of\ cookies=c\\\\Cost\ of\ 1\ cookie=\$2\\\\Earning\ from\ cookies=2\times c=2c

Total\ earning=Earning\ from\ cookies+Earning\ from\ cookies+Earning\ from\ chocolate\ bars\\\\Total\ earning=30+2c

Carl wants to raise at least \$55

Total\ earning\geq 55\\\\2c+30\geq 55\\\\2c\geq 55-30\\\\2c\geq 15\\\\c\geq7.5

7 0
3 years ago
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