Answer:
Oxidation, Reduction
Explanation:
A redox reaction is a short form for reduction-oxidation.
Reduction is a term which means that electron is gained while oxidation is a term which means that electron Is lost.
The species that gain electron is known as the oxidizing agent while the species losing electrons is known as the reducing agent

The solid product from reaction of sulfuric acid with sucrose is?

- Concentrated <u>sulfuric acid</u> is added to sucrose forming carbon, steam and <u>sulfur</u> dioxide.
<h2>--------------------------------------------------------------------------------</h2>
<h3>RELATED TO THE QUESTION </h3>

- <u>Solid is one of the four fundamental states of matter</u>. The molecules in a solid are closely packed together and contain the least amount of kinetic energy.
- <u>A solid is characterized by structural rigidity and resistance to a force applied to the surface</u>.

- <u>Sulfuric acid or sulphuric acid, also known as oil of vitriol, is a mineral acid composed of the elements sulfur, oxygen and hydrogen</u>, with molecular formula H₂SO₄. It is a colorless, odorless and viscous liquid that is miscible with water at all concentrations.

- <u>Sucrose is common sugar. It is a disaccharide</u>, a molecule composed of two monosaccharides: glucose and fructose. Sucrose is produced naturally in plants, from which table sugar is refined. It has the molecular formula C₁₂H₂₂O₁₁.
#CarryOnLearning
#LetsEnjoyTheSummer
<h3>→XxKim02xX</h3>
I have provided the steps and solution within the attachment. The pH of the solution would be 12.30, this indicates that the solution is basic, as a higher value of pH indicates presence of more hydroxide ions and less of hydrogen ions in the solution.
Answer:
52.206 kg
Explanation:
From the given information:
Mass of hexane C6H14 = 
= 7391.9 g
Mass of octane C8H18 = 
= 2682.7 g
Mass of decane C10H22 = 
= 9225.4 g
However, recall that:
number of moles of an atom = mass/molar mass
∴
For hexane, no of moles = 7391.9 g/86.18 g/mol
= 85.77 moles
For octane, no of moles = 2682.7 g/114.23 g/mol
= 23.49 moles
For decane, no of moles = 9225.4 g/142.29 g/mol
= 64.84 moles
Therefore:
number of moles of CO2 produced = (6 × 85.77)+(23.49)+(10×64.84) moles
= 1186.51 moles
Finally, the mass of CO2 produced is:
= 1186.51 mol × 44 g/mol
= 52206.44 g
= 52.206 kg