Answer:
37.1 kilograms of ammonia gas will be produced in this process
Explanation:
The percentage yield of the reaction is given by:
According to question
The percentage yield of the given industrial process = 74.0%
The given theoretical yield of ammonia gas = 50.1 kg
The experimental yield of ammonia gas = x
The percentage yield of the reaction is calculated a:
Solving for x, we get:
37.1 kilograms of ammonia gas will be produced in this process
Answer:
On the particulate level: 1 molecule of H₂(g) reacts with 1 molecule of Cl₂(g) to form 2 molecules of HCl(g).
On the molar level: 1 mole of H₂(g) reacts with 1 mole of Cl₂(g) to form 2 moles of HCl(g).
Explanation:
Let's consider the following equation.
H₂(g) + Cl₂(g) → 2 HCl(g)
We can use the balanced equation to interpret the changes in two levels: the particulate level and the molar level.
On the particulate level, we consider discrete molecules.
On the particulate level: 1 molecule of H₂(g) reacts with 1 molecule of Cl₂(g) to form 2 molecules of HCl(g).
On the molar level, we think in terms of moles, considering 1 mole of particles = 6.02 × 10²³ particles.
On the molar level: 1 mole of H₂(g) reacts with 1 mole of Cl₂(g) to form 2 moles of HCl(g).
Answer:
It does not have a regular composition.
Explanation:
An insoluble solid formed during a reaction is called a Precipitate.
