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Mekhanik [1.2K]

3 years ago

8

When Johnny woke up at 8am, it was 14 degrees below zero. Every 2 hours, the temperature dropped 4 degrees. What is the temperat

ure at noon? Group of answer choices
6

-6

-22

22

2 answers:

sweet-ann [11.9K]3 years ago

8 0

Answer:

-22

Step-by-step explanation:

Rainbow [258]3 years ago

3 0

Answer:

aasdfghjkllknhgfdsazxcvhjk

Step-by-step explanation:

zsxdcfvgbhnj

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How do work this out

BabaBlast [244]

We can factor this by using grouping. Take the leading coefficient and multiply it by the constant. In this case we get 5*-7 = -35.

Now we need 2 numbers that add to 2 and multiply to be -35. The numbers are -5 and 7.

So split the 2r into these two terms and group.

(5r^2 - 5r) + (7r - 7)

Factor both groups.

5r(r-1) + 7(r-1)

The factors of (r-1) can be added together to get the answer.

(r-1)(5r+7)

6 0

3 years ago

PLEASE HELP!!!!!<br> will mark brainliest!!!!!

PSYCHO15rus [73]

Answer:

x y

4 7

5 -1

6 -9

5 0

3 years ago

Read 2 more answers

So I took a test from my teachers desk and took photos of the test questions. I am indeed cheating but I just want to know the a

romanna [79]

Answer:

THE CORRECT OPTION IS A) Δ ABC $\sim$ Δ BDC $\sim$ Δ ADB

Step-by-step explanation:

The first option is in correct order of triangle ,we can easily the their sides are proportionate . And having eqal angles.

8 0

3 years ago

Describe the relationship between the<br> values of the digits in the number

Lelechka [254]

Answer:

Step-by-step explanation:

The relationship between the values of the digits in the number 9,999,999 is that, the value of each digit is 10 times of the value of the ...

8 0

2 years ago

What is the asymptote for the graph of this logarithmic function?<br><br> f(x) = log3(x – 1)

Pepsi [2]

Answer:

Vertical Asymptote:

$x=1$

Horizontal asymptote:

it does not exist

Step-by-step explanation:

we are given

$f(x)=log_3(x-1)$

Vertical asymptote:

we know that vertical asymptotes are values of x where f(x) becomes +inf or -inf

we know that any log becomes -inf when value inside log is zero

so, we can set value inside log to zero

and then we can solve for x

$x-1=0$

we get

$x=1$

Horizontal asymptote:

we know that

horizontal asymptote is a value of y when x is +inf or -inf

For finding horizontal asymptote , we find lim x-->inf or -inf

$\lim_{x \to \infty} f(x)= \lim_{x \to \infty}log_3(x-1)$

$\lim_{x \to \infty} f(x)=log_3(\infty-1)$

$\lim_{x \to \infty} f(x)=undefined$

so, it does not exist

7 0

3 years ago

Read 2 more answers