Answer:
Lateral area =
pi * (radius) * √ [ height ^2 + radius^2 ] =
pi * ( 4 ) * √ [ 4^2 + 3^2 ] =
pi * ( 4 ) * √25 =
pi * ( 4 ) * (5 ) =
20 pi units^2 ≈ 62.8 units^2
Step-by-step explanation:
Do you have the rest of the question?
(i) There is glucose outside the Visking tubing. Glucose is small enough to pass through it.
(iii) Normal urine color ranges from pale yellow to deep amber — the result of a pigment called urochrome and how diluted or concentrated the urine is. Pigments and other compounds in certain foods and medications can change your urine color. Beets, berries and fava beans are among the foods most likely to affect the color.
LINK: https://www.mayoclinic.org/diseases-conditions/urine-color/symptoms-causes/syc-20367333
I HOPE THIS HELPS. IF IT DOES, PLEASE MARK BE AS BRAINLIEST. EVERYTHING ELSE IS CORRECT EXEPT (i)

common difference is
3.6 - 5.8 = -2.2
let T1 = 5.8
T2 = 3.6
assuming we are to find T2
T2 = T(2-1) -2.2
= T1 -22
= 5.8 -2.2
= 3.6
Answer:

Step-by-step explanation:
In this exercise, we have two equations, namely:

And we are asked to solve this problem by graphing. In this way, we can write a system of linear equations in two variables, but first of all, let's rewrite:

Then:

So here we have two lines.
The first one is:

This line passes through the origin and has a slope 
The second one is:

This line has a slope
and cuts the y-axis at 
By using graph tools, we get the graph shown below, then:
