Answer: After 3 hours both will have the same cost.
Step-by-step explanation:
Let x = Number of hours and y be the total cost.
Total cost = Initial cost + (cost per hour)(Number of hours)
At Mike's Bounce Shop,
Total cost (y)= 30+2x
At Jose's Bounce Rentals,
Total cost(y) = 12+8x
When both shops have the same cost, then
Total cost = 12+8(3)=12+24=$36
Hence, After 3 hours both will have the same cost.
The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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300 x .15 y te dará la respuesta
The answer is C
y=kx. where k is a constant
sub y=34,x=2
2k=34
k=17
The probability of rolling an even number on the first dice is 1/2(3/6)
The probability of rolling an even number on the first dice is also 1/2 (3/6)
So the probability of getting two even numbers on both dice is 1/2*1/2=1/4
