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vovikov84 [41]
3 years ago
9

Solve the equation below: -12x + 8 + 5x =36

Mathematics
2 answers:
gogolik [260]3 years ago
6 0

Answer:

-12x + 8 + 5x =36

-7x = 36 - 8

-7x = 28

x = 28/-7

x = -4

ivolga24 [154]3 years ago
4 0

Answer:

-12x+5x=28

-7x=28

x= -4

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pantera1 [17]

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Find the area of a regular pentagon with apothem length 5 in. Round to the nearest tenth.
marishachu [46]
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7 0
4 years ago
Match the rates with their equivalent unit rates. Match the rates with their equivalent unit rates. arrowRight arrowRight arrowR
anyanavicka [17]

Answer:

\frac{47}{2} \to 6

\frac{60}{12} \to 5

\frac{40}{10} \to 4

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Step-by-step explanation:

Given

See attachment

Required

Complete the blanks

To do this, we simply carry out the division operation.

So, we have:

\frac{47}{2} \to 6

\frac{60}{12} \to 5

\frac{40}{10} \to 4

\frac{56}{8} \to 7

\frac{64}{8} \to 8

6 0
3 years ago
Read 2 more answers
Suppose θ is an angle in the standard position whose terminal side is in Quadrant III and sec θ=61/60. Find the exact values of
Nataly_w [17]

Answer:

Part 1) cos(\theta)=-\frac{60}{61}

Part 2) tan(\theta)=\frac{11}{60}  

Part 3) cot(\theta)=\frac{60}{11}

Part 4) csc(\theta)=-\frac{61}{11}

Part 5) sin(\theta)=-\frac{11}{61}  

Step-by-step explanation:

we know that

If angle theta lie on Quadrant III        

then

The function sine is negative

The function cosine is negative        

The function tangent is positive

The function cotangent is positive

The function cosecant is negative

The function secant is negative

step 1

Find cos(\theta)  

we know that

cos(\theta)=\frac{1}{sec(\theta)}

we have

sec(\theta)=-\frac{61}{60} ----> the value must be negative

therefore

cos(\theta)=-\frac{60}{61}

step 2

Find tan(\theta)

we know that

tan^{2} (\theta)+1=sec^{2} (\theta)

we have

sec(\theta)=-\frac{61}{60}

substitute

tan^{2} (\theta)+1=(-\frac{61}{60})^{2}

tan^{2} (\theta)+1=\frac{3,721}{3,600}

tan^{2} (\theta)=\frac{3,721}{3,600}-1

tan^{2} (\theta)=\frac{121}{3,600}

tan(\theta)=\frac{11}{60}

step 3

Find cot(\theta)

we know that

cot(\theta)=\frac{1}{tan(\theta)}

we have

tan(\theta)=\frac{11}{60}

therefore

cot(\theta)=\frac{60}{11}

step 4

Find csc(\theta)

we know that

cot^{2} (\theta)+1=csc^{2} (\theta)

we have

cot(\theta)=\frac{60}{11}

substitute

(\frac{60}{11})^{2}+1=csc^{2} (\theta)

\frac{3,600}{121}+1=csc^{2} (\theta)

\frac{3,721}{121}=csc^{2} (\theta)

square root both sides

csc(\theta)=-\frac{61}{11}

step 5

Find sin(\theta)

we know that

sin(\theta)=\frac{1}{csc(\theta)}

we have

csc(\theta)=-\frac{61}{11}

therefore

sin(\theta)=-\frac{11}{61}

7 0
3 years ago
Read 2 more answers
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