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3 years ago

A ball is thrown through the air.What condition(s) would enable the ball to continue in its state of motion?

Physics

2 answers:

Natasha_Volkova [10]3 years ago

7 0

Answer:

C) No air resistance or gravity

Explanation:

For headwind imagine an airplane flying. The wind is hitting the front of the aircraft. Just like the wind is hitting the front of the ball. This increases the drag force and the ball will eventually slow and let the force of gravity act.

For tailwind imagine a sailboat. The wind catches the sail a pushes the boat. Both the wind and boat are going the same way so the angle of the wind is coming from behind. This is why it is called a tail wind.

If a ball is thrown, it has wind resistance and gravity. Otherwise just imagine the ball traveling all around the earth. Because the ball only has the force of lift and thrust, the ball will stay in motion until it hits something strong enough to counteract its thrust.

The description does not state any contact with another object. Also the ball will immediately stop if it has less newtons of force.

Aleksandr-060686 [28]3 years ago

5 0

I think that the answer is c but I’m not sure

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Light travels from the sun to the earth, a distance of 144,000,000,000 meters, in 480 seconds. Calculate the approximate velocit

mel-nik [20]

Answer:

The answer is C.) 300,000,000 m/s

Explanation:

Light travels at a constant rate of 300,000,000 m/s. this can be determined by dividing the distance (144,000,000,000 meters) by the time (480 seconds). that's pretty fast. in fact, nothing can travel any faster than this. ever.

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3 years ago

A(n) 60.3 g ball is dropped from a height of 53.7 cm above a spring of negligible mass. The ball compresses the spring to a maxi

Feliz [49]

Answer:

271.862 N/m

Explanation:

From Hook's Law,

mgh = 1/2ke²............... Equation 1

Where

m = mass of the ball, g = acceleration due to gravity, k = spring constant, e = extension, h = height fro which the ball was dropped.

Making k the subject of the equation,

k =2mgh/k²....................... Equation 2

Note: The potential energy of the ball is equal to the elastic potential energy of the spring.

Given: m = 60.3 g = 0.0603 kg, g = 9.8 m/s², e = 4.68317 cm = 0.0468317 m, h = 53.7 cm = 0.537 m

Substitute into equation 2

k = 2(0.0603)(9.8)(0.537)/0.048317²

k = 0.6346696/0.0023345

k = 271.862 N/m

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4 years ago

What do electrons in the same shell have in common? AThey have the same amount of energy incorrect answer BThey are all positive

Keith_Richards [23]

Answer:

They have the same amount of energy

Explanation:

Electrons are said to be the subatomic particles that move around the nucleus of an atom. These electrons are negatively charged particles that are seen to be quite smaller than the nucleus of an atom.

The electron shells of these atoms are usually being filled from the inside out with the low-energy shells closer to the nucleus being filled before they can go into the much higher-energy shells that are a bit out

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3 years ago

the 200 g baseball has a horizontal velocity of 30 m/s when it is struck by the bat, B, weighing 900 g, moving at 47 m/s. during

Ivanshal [37]

Solution :

Given :

Mass of the baseball, m = 200 g

Velocity of the baseball, u = -30 m/s

Mass of the baseball after struck by the bat, M = 900 g

Velocity of the baseball after struck by the bat, v = 47 m/s

According to the conservation of momentum,

$Mv+mu=Mv_1+mv_2$