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Dominik [7]
3 years ago
15

a 64 l gas tank is filled completely is 15 degree celsius how much gasoline overflows into can get up to 35 degree celsius while

the car is parked in direct sunlight​
Physics
1 answer:
o-na [289]3 years ago
3 0

Answer:

Volume of gasoline overflow(v)= 40/9 L (I.e. 4.44 L)

Explanation:

Use <u>v1</u><u>/</u><u>T1</u><u>=</u><u>v2</u><u>/</u><u>T2</u>

.....overflow(V)=v2-v1

<u>Note</u><u>;</u> <em>Take</em><em> </em><em>temperature</em><em> </em><em>in</em><em> </em><em>absolute</em><em> </em><em>scale</em><em> </em><em>or</em><em> </em><em>kelvin</em><em> </em><em>scale</em><em> </em>

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Speed= ?
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Which term is defined as the change in the direction of light when it goes from one medium into a different medium?
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Help please, I don't get it​
Sergio [31]

Answers:

a) \hat F=(0.83,-0.55) N

b) \hat D=(-0.44,-0.89) m

c) \hat V=(-0.47,0.88) m/s

Explanation:

A unit vector is a vector whose magnitude (length) is equal to 1. This kind of vector is identified as \hat v and the way to calculate is as follows:

\hat v=\frac{\vec v}{|v|}

Where:

\vec v=(x,y) is the vector

|v|=\sqrt{x^{2}+y^{2}} is the magnitude of the vector

Having this information clarified, let's begin with the answers:

a) Force Vector

\vec F=(9.0 \hat i - 6.0 \hat j) N

Magnitude of \vec F:

|F|=\sqrt{(9.0 \hat i)^{2}+(-6.0 \hat j)^{2 }}N=10.81 N

<u />

<u>Unit vector:</u>

\hat F=\frac{\vec F}{|F|}

\hat F=\frac{(9.0 \hat i - 6.0 \hat j) N}{10.81 N}

\hat F=\frac{9.0}{10.81} N-\frac{6.0}{10.81}N

\hat F=(0.83,-0.55) N

b) Displacement Vector

\vec D=(-4.0 \hat i - 8.0 \hat j) m

Magnitude of \vec D:

|D|=\sqrt{(-4.0 \hat i)^{2}+(-8.0 \hat j)^{2 }}m=8.94 m

<u />

<u>Unit vector:</u>

\hat D=\frac{\vec D}{|D|}

\hat D=\frac{(-4.0 \hat i - 8.0 \hat j) m}{8.94 m}

\hat D=\frac{-4.0}{8.94} Nm+\frac{-8.0}{8.94}m

\hat D=(-0.44,-0.89) m

c) Velocity Vector

\vec V=(-3.50 \hat i + 6.50 \hat j) m/s

Magnitude of \vec V:

|V|=\sqrt{(-3.50 \hat i)^{2}+(6.50 \hat j)^{2}}m/s=7.38 m/s

<u />

<u>Unit vector:</u>

\hat V=\frac{\vec V}{|V|}

\hat V=\frac{(-3.50 \hat i +6.50 \hat j) m/s}{7.38 m/s}

\hat V=\frac{-3.50}{7.38} m/s+\frac{6.50}{7.38}m/s

\hat V=(-0.47,0.88) m/s

8 0
4 years ago
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