Answer:A
Explanation:
In R-L circuit current is given by
![i=i_0\left [ 1-e^{\frac{-t}{L/R}}\right ]](https://tex.z-dn.net/?f=i%3Di_0%5Cleft%20%5B%201-e%5E%7B%5Cfrac%7B-t%7D%7BL%2FR%7D%7D%5Cright%20%5D)
where i=current at any time t
R=resistance
L=Inductance
at t=0 
approaches to 1
therefore ![i=i_0\left [ 1-1\right ]](https://tex.z-dn.net/?f=i%3Di_0%5Cleft%20%5B%201-1%5Cright%20%5D)
i=0
when t approaches to 
, approaches to zero
thus 
thus we can say that initially circuit act as broken wire with zero current
and it increases exponentially with time and act as ordinary connecting wire
Answer: 1.88 N
Explanation:
Data:
Force = 4.00N
angle = 62°
horizontal force = ?
Solution:
The trigonometric ratio that relates horizontal - leg to hypotenuse is the cosine.
That ratio is:
horizontal - leg
cos(angle) = -------------------------
hypotenuse
So, applied to the force, that is:
horizontal force
cos (angle) = -----------------------------------
total force
So, clearing the horizontal component you get:
horizontal force = force * cos (angle)
Substitute the data given:
horizontal force = 4.00N * cos(62°) = 4.00N * 0.4695 = 1.88 N
Answer: 1.88N
Output Force, hope this helps.
Using kinematic equation s=ut + 1/2 at^2(u = initial velocity=0, s=120m, t= 6.32s), 120 = 0(t) + 1/2 a(6.32)^2. a = 120x2/(6.32)^2 = 6m/s^2.
Answer:
dababy
Explanation:
dababy is the best and that's the answer
