46:56

Name at least two benefits of using models in science.

aliina [53]

Explanation:

1) it gives you a visual of what you will be doing

2) you can find more variables when looking at it compared to just thinking of it

3) gives you new insights on what is yet to come

4) allows you to answer some questions and begin testing

7 0

3 years ago

Read 2 more answers

Temperature has no significance during the calculation of numerical .why?? <br>^_^

Brums [2.3K]

Answer:

Explanation:

concepts, such as the internal energy of a system; heat or sensible heat, which are defined as types of energy transfer (as is work); or for the characteristic energy of a degree of freedom in a thermal system {\displaystyle kT}kT, where {\displaystyle T}T is temperature and {\displaystyle k}k is the Boltzmann constant.

7 0

3 years ago

How many moles are in 15.2 grams of Calcium (Ca)?

nalin [4]

Answer:

There are 0.379 moles of Ca in the given sample.

Explanation:

Hey there!

We're given that we have 15.2 grams of Ca (Calcium). We need to convert grams to moles.

There are many different conversion types for moles. A few examples are:

grams to moles
moles to grams
grams to particles
moles to liters

There are really endless possibilities for conversion factors. Since we want to find the number of moles in a certain sample, we first need to define what a mole is.

<u>Mole</u> - a unit of measurement in chemistry

A mole is one unit of a certain item. For instance, one cup would be equivalent to one mole. Moles are simply a hypothetical unit in chemistry that act as a placeholder.

<u>Now, how do we find the number of moles?</u>

We know that a mole of something is one of that substance. In this case, we're referring to one atom of Calcium.

Therefore, we need to reference a periodic table to understand what the mass of one atom of calcium is equivalent to. I'll be using the official AP Chemistry periodic table as issued by the College Board.

When we reference the periodic table, we see the mass of one atom of calcium is equivalent to 40.08 amu (atomic mass units).

We learn in chemistry that we can use the terms amu and grams interchangeably, so we have learned that one mole of calcium is equivalent to 40.08 grams.

Now, we need to find out how many moles are in 15.2 grams of calcium. We can use dimensional analysis to work this out.

Our starting unit will be 15.2 grams of Ca.

$\text{15.2 grams Ca}$

We want to convert this into moles, so we need to cancel out our grams value. Additionally, since we know that we have 40.08 grams of Ca in one mole, we can set these up as two ratios:

$\displaystyle \frac{\text{40.08 grams Ca}}{\text{1 mole Ca}}$
$\displaystyle \frac{\text{1 mole Ca}}{\text{40.08 grams Ca}}$

These ratios can be used to express the relationship between the moles of calcium and the mass of one calcium atom. However, we need our value of grams to cancel out, so since we will be using cross multiplication in our dimensional analysis, we need to use the ratio with grams on the bottom.

Now that we have selected our ratio, we can set up a multiplication problem of our two ratios:

$\displaystyle \text{15.2 grams Ca} \times \frac{\text{1 mole Ca}}{\text{40.08 grams Ca}}$

We assume that we have a denominator of 1 below 15.2 grams Ca.

Now, we perform our multiplication.

$\displaystyle \frac{\text{15.2 grams Ca} \ \times \ \text{1 mole Ca}}{\text{40.08 grams Ca}}$

We see that our remaining unit is going to be mole(s) Ca, so we can go ahead and drop our grams Ca unit.

$\displaystyle \frac{\text{15.2} \ \times \ \text{1 mole Ca}}{\text{40.08}}$

Now, we need to simplify a little bit.

$\displaystyle \frac{\text{15.2}}{\text{40.08}} = \text{? moles Ca}$

Finally, let's divide our fraction and evaluate our equation to find the value of moles Ca.

$\displaystyle \frac{15.2}{40.08} = \text{0.379241517 moles Ca}$

Not just yet! To complete our work, we need to find the number of significant figures we can use. We are given two values in which we can use to judge how many significant figures we are limited to.

15.2 -- Three significant figures
40.08 -- Four significant figures

In chemistry, we always use the least number of significant figures for precision calculations, so we need to round our answer to three significant figures.

$0.379241517 \approx 0.379$