What volume of methanol should be used to make 1.25 L of a 21.0 % by volume solution?

Chemistry

1 answer:

e-lub [12.9K]3 years ago

6 0

Answer:

0.2625L

Explanation:

Given parameters":

Volume of solution = 1.25L

Percentage concentration = 21%

Unknown:

Volume of methanol = ?

Solution:

The percentage concentration is one of the different methods for expressing concentration values.

It is given as:

Percentage concentration = $\frac{Volume of solute}{volume of solution} x 100$

Now we have to work backwards to derive the percentage concentration;

let the unknown, the volume of methanol which is the solute = P;

21 = $\frac{p}{1.25}$ x 100

21 = $\frac{100p}{1.25}$

21 = 80p

p = 0.2625L

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