Answer:
![x=\frac{5(+/-)\sqrt{25-8a}} {2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B5%28%2B%2F-%29%5Csqrt%7B25-8a%7D%7D%20%7B2a%7D)
Step-by-step explanation:
we know that
The formula to solve a quadratic equation of the form
![ax^{2} +bx+c=0](https://tex.z-dn.net/?f=ax%5E%7B2%7D%20%2Bbx%2Bc%3D0)
is equal to
![x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%28%2B%2F-%29%5Csqrt%7Bb%5E%7B2%7D-4ac%7D%7D%20%7B2a%7D)
in this problem we have
![ax^{2} -5x+2=0](https://tex.z-dn.net/?f=ax%5E%7B2%7D%20-5x%2B2%3D0)
so
![a=a\\b=-5\\c=2](https://tex.z-dn.net/?f=a%3Da%5C%5Cb%3D-5%5C%5Cc%3D2)
substitute in the formula
![x=\frac{5(+/-)\sqrt{-5^{2}-4(a)(2)}}{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B5%28%2B%2F-%29%5Csqrt%7B-5%5E%7B2%7D-4%28a%29%282%29%7D%7D%7B2a%7D)
![x=\frac{5(+/-)\sqrt{25-8a}} {2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B5%28%2B%2F-%29%5Csqrt%7B25-8a%7D%7D%20%7B2a%7D)
Answer:
=(a-b)(a^2+ab+b^2)
= a^3+a^2b+ab+ab^2-ba^2-ab^2-b^3
SIMPLIFY
=a^3+ab-b^3
A square has four corners.
Answer:
0.25
Step-by-step explanation:
3/12 = 1/4
1÷4= 0.25
Answer: y=2x-1
We know that the equation of a line is y = mx + b, where m is the gradient and b is the y-intercept.
First to find the gradient, we use the formula y2-y1/x2-x1.
x1 and y1 being the first set of coordinates (2,3) and x2 and y2 being the second set (4,7)
Now we sub in:
m=7-3/4-2
m=4/2
m=2
This is our gradient and we can put it into the equation: y=2x+b
Now we find the y-intercept (b). Since the y-intercept isn’t shown, we can sub in the coordinates to find it.
y=2x+b
Sub (2,3)
3=2(2)+b
3=4+b
-1=b
Sub (4,7)
7=2(4)+b
7=8+b
-1=b
Subbing in both coordinates gives us -1 as the y-intercept, so the finished equation is: y=2x-1